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11 months ago

Maths Statistics

24. From the prices of shares X and Y below, find out which is more stable in value:

X	35	54	52	53	56	58	52	50	51	49
Y	108	107	105	105	106	107	104	103	104	101

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Payal Gupta

Contributor-Level 10

24. We can tabulate the given data as follows.

Total =

Mean of $x, \bar{x} = \frac{\sum_{}^{} x i}{n} = \frac{510}{10} = 51 .$

Mean of $Y, \bar{Y} = \frac{\sum_{}^{} Y i}{n} = \frac{1050}{10} = 105$ .

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New answer posted

11 months ago

Maths Statistics

Class 11 Maths Statistics exercise 13.3 Solution

23. From the data given below state which group is more variable, A or B?

Marks	10-20	20-30	30-40	40-50	50-60	60-70	70-80
Group A	9	17	32	33	40	10	9
Group B	10	20	30	25	43	15	7

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Payal Gupta

Contributor-Level 10

23. Let the assumed mean be A=45 and h=10. Then we can tabulate the given data as following.

$\begin{matrix} = \frac{- 6}{150} * 10 + 45 . \end{matrix}$

= 44.6

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New question posted

11 months ago

Maths Statistics

Class 11 Maths Statistics exercise 13.3 Solution

23. From the data given below state which group is more variable, A or B?

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New answer posted

11 months ago

Maths Statistics

22. The diameters of circles (in mm) drawn in a design are given below:

Diameters	33-36	37-40	41-44	45-48	49-52
No. of circles	15	17	21	22	25

Calculate the standard deviation and mean diameter of the circles.

[ Hint First make the data continuous by making the classes as 32.5-36.5, 36.5-40.5, 40.5-44.5, 44.5 - 48.5, 48.5 - 52.5 and then proceed.]

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Payal Gupta

Contributor-Level 10

22. The given data is converted into continuous frequency duration by subtracting and adding 0.5 from lower and upper limit respectively. Lit the assumed mean be A=42.5 and h=4

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11 months ago

Maths Statistics

21. Find the mean, variance and standard deviation using short-cut method

Height in cms	70-75	75-80	80-85	85-90	90-95	95-100	100-125	105-110	110-115
Frequencies	3	4	7	7	15	9	6	6	3

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Payal Gupta

Contributor-Level 10

21. Let the assumed mean be A=92.5 and h=5

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11 months ago

Maths Statistics

20.

Classes	0-10	10-20	20-30	30-40	40-50
Frequencies	5	8	15	16	6

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Payal Gupta

Contributor-Level 10

20.

We have, $N = \sum_{i = 1}^{n} f i = 50$ .

So, mean, $\bar{x} = \frac{1}{N} * \sum_{i = 1}^{n} f i x i = \frac{1350}{5} = 27 .$

$\begin{matrix} = \frac{1}{50} * 6600 \end{matrix}$

= 132.

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New answer posted

11 months ago

Maths Statistics

19. Find the mean and variance for the following frequency distributions in Exercises 19 and 20.

Classes	0-30	30-60	60-90	90-120	120-150	150-180	180-210
Frequencies	2	3	5	10	3	5	2

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Payal Gupta

Contributor-Level 10

19. Let the assumed mean be A=105 and class width, h=30. The given data can be tabulated as

= 2280 - 4

= 2276.

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11 months ago

Maths Statistics

19. Find the mean and variance for the following frequency distributions in Exercises 19 and 20.

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New answer posted

11 months ago

Maths Statistics

18.Find the mean and standard deviation using short-cut method.

*x_i*	60	61	62	63	64	65	66	67	68
*f_i*	2	1	12	29	25	12	10	4	5

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Payal Gupta

Contributor-Level 10

18. Let the assumed mean be A=64 and it the width, h=1.

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11 months ago

Maths Statistics

17.

*x_i*	92	93	97	98	102	104	109
*f_i*	3	2	3	2	6	3	3

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Payal Gupta

Contributor-Level 10

17. The given data can be tabulated as follow

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Class 11 Maths Statistics exercise 13.3 Solution

Class 11 Maths Statistics exercise 13.3 Solution

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