Motion in a Plane
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New answer posted
5 months agoContributor-Level 10
4.11
(a) Total distance travelled = 23 km, Total time taken = 28 min
Average speed = = km/min = 49.29 km/h
(b) Average velocity = = km/min = 21.43 km/h
New answer posted
5 months agoContributor-Level 10
4.10

Since the motorist taking the 60° turn after every 500m, It will form a perfect hexagon of side 500m after 6 turns.
Suppose the motorist starts from point A. From A, turns 60° to reach B (first turn), then to C and so on.
1. At third turn, The magnitude of displacement = DG + GA = 500m + 500m = 1000m Total path length = AB + BC + CD = 500m +500m +500m = 1500 m
2. At sixth turn, When the motorist takes the 6th turn, he is at starting point A. Therefore,
The magnitude of displacement = 0Total path length = AB + BC + CD + DE + EF + FA = 500m + 500m
New answer posted
5 months agoContributor-Level 10
4.9
(a) Since the cyclist came back to his starting point O, so the displacement is Zero
(b) Average velocity = = 0
(c) Average speed =
Distance travelled = OP + PQ + QO
= 1 + (1/4) 3.57 km
Average speed = 3.57 / 10 km/min = 21.43 km/h
New answer posted
5 months agoContributor-Level 10
4.8 The radius of the ground = 200 m, the distance PQ = diameter of the ground = 400 m
The displacement all 3 girls = 400 m
This magnitude is equal to the path skated by girl B
New answer posted
5 months agoContributor-Level 10
4.7
(a) This statement is In order to make a + b+ c + d = 0, it is not necessary to have all four given vectors to be null vectors.
(b) a + b + c +d = 0, ( a + c ) = - (b + d)
Taking the magnitude of both LHS and RHS, | a + c| = | -(b + d)| = | b + d|
So the statement is True.
(c) Given a + b + c + d = 0, a = - (b + c + d)
Taking magnitude of both LHS and RHS, |a| = | -( b + c+ d)| = |b + c +d|
|a| ……….(1)
Equation (1) shows that the magnitude of a can never be greater than the sum of magnitudes of b,c and d. So the statement is True.
(d) In the given expression a + b + c + d = 0, the sum of 3 vectors a, (b+c), d ca
New answer posted
5 months agoContributor-Level 10
(a)

We can write
=
= = ………(ii)
=
In a triangle, each side is smaller than the sum of the other two sides. Therefore in ΔOMN, we have ON < (OM + MN)
< + ….(iv)
If the two vectors and act along a straight line in the same direction, then we can write = +
Combining equations (iv) and (v), we get
+
(b)

Let two vectors and be represented by the adjacent sides of a parallelogram OMNP.
We can write
=
= = ………(ii)
New answer posted
5 months agoContributor-Level 10
4.5
(a) The magnitude of a vector is a number only, hence always a scalar – TRUE
(b) Each component of a vector is also a vector – FALSE
(c) The total path length is a scalar quantity, whereas displacement is a vector quantity. – FALSE
(d) The total path length is always greater than or equal to the magnitude of displacement of a particle – TRUE
(e) Three vectors which do not lie in a plane can never add up to give a null vector – TRUE
New answer posted
5 months agoContributor-Level 10
4.4
(a) The addition of two scalar quantities is meaningful – if they both represent the same physical quantity.
(b) The addition of a vector quantity with a scalar quantity is not meaningful.
(c) Multiplying a scalar with a vector is meaningful.
(d) The multiplication of two scalar quantities is meaningful.
(e) The addition of two vectors is meaningful.
(f) Adding a component of a vector to the same vector is meaningful.
New answer posted
5 months agoContributor-Level 10
4.3 Impulse is the only vector quantity from the above list. Impulse is the product of force and time. Force is a vector quantity and time is a scalar quantity. The product of 1 vector and 1 scalar is always a vector quantity.
New answer posted
5 months agoContributor-Level 10
4.2 Work & Current are scalar quantities. Work is the product of Force and displacement. Since the product of two vectors quantities are always scalar. Current is independent of direction, it is only magnitude, hence scalar.
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