Ncert Solutions Chemistry Class 12th

Based upon properties of drugs.

Melamine + formaldehyde ->  Melamine formaldehyde polymer

Kindly consider the following figure

Kindly consider the following figure

Kindly consider the following figure

Let initial moles of reactant taken = n. Total moles obtained for benzene sulphonic acid = 0.6 n (with % yield = 60%)

Moles of benzene sulphonic acid before reaction II = 0.6n

Moles obtained for phenol (with % yield 50%) = 0.6 * 0.5 n = 0.3 n

So, overall % age yield of complete

reaction = $\frac{0.3n}{n}*100=30\mathrm{\%}$  

Oxidation of HCHO (a) will produce HCOOH, which is produced by ants.

$\mathrm{\%}Opticalpurity=\frac{Observedrotationofmixture*100}{rotationofpureenautiomer}$

$=\frac{+12.6}{+30}*100=42\mathrm{\%}$

  $2KMn{O}_4+5H_2{\stackrel{+3}{C}}_2{O}_4+3H_{2}S{O}_4\left(dil\right)\to K_{2}S{O}_4+2MnS{O}_4+10C{\stackrel{+4}{O}}_2+8H_{2}O$

Oxidation state of carbon changes from +3 to +4

$\therefore$ change in O. S is 1

Solubility of CaF₂ = S mol/L

$S=\frac{2.34*10^{-3}}{0.1*78}=\frac{2.34}{78}*10^{-2}=3*10^{-4}mol/L$          

$K_{sp}\left(Ca{F}_2\right)=4S^3=4{\left(3*10^{-4}\right)}^3=108*10^{-12}$        

= 0.0108 * 10^-8 (mol/L)³