Ncert Solutions Chemistry Class 12th

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}LetI={\displaystyle \underset{0}{\overset{1}{\int }}\underset{II}{xlog}}\underset{I}{\left|1+2x\right|}dx\\ ={\left[log\left|1+2x\right|.\left(\frac{x^2}{2}\right)\right]}_0^1-{\displaystyle \underset{0}{\overset{1}{\int }}\left(\frac{1.2}{1+2x}.\frac{x^2}{2}\right)}dx\\ =\frac{1}{2}{\left[x^{2}log\left(1+2x\right)\right]}_0^1-{\displaystyle \underset{0}{\overset{1}{\int }}\left(\frac{x^2}{1+2x}\right)}dx\\ =\frac{1}{2}\left[log3-0\right]-{\displaystyle \underset{0}{\overset{1}{\int }}\left(\frac{x}{2}-\frac{x/2}{1+2x}\right)}dx\\ =\frac{1}{2}log3-\frac{1}{2}{\displaystyle \underset{0}{\overset{1}{\int }}x}dx+\frac{1}{2}{\displaystyle \underset{0}{\overset{1}{\int }}\frac{x}{1+2x}}dx\\ =\frac{1}{2}log3-\frac{1}{2}{\left[\frac{x^2}{2}\right]}_0^1+\frac{1}{2}.\frac{1}{2}{\displaystyle \underset{0}{\overset{1}{\int }}\frac{\left(2x+1-1\right)}{1+2x}}dx\\ =\frac{1}{2}log3-\frac{1}{4}\left[1-0\right]+\frac{1}{4}{\displaystyle \underset{0}{\overset{1}{\int }}1dx}-\frac{1}{4}{\displaystyle \underset{0}{\overset{1}{\int }}\frac{1}{2x+1}dx}\\ =\frac{1}{2}log3-\frac{1}{4}+\frac{1}{4}{\left[x\right]}_0^1-\frac{1}{4}.\frac{1}{2}{\left[log\left|2x+1\right|\right]}_0^1\\ =\frac{1}{2}log3-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}\left[log3-0\right]\\ =\frac{1}{2}log3-\frac{1}{8}log3=\frac{3}{8}log3\\ Hence,I=\frac{3}{8}log3.\end{array}$

This is a Long Answer Type Questions as classified in NCERT Exemplar

This is a Long Answer Type Questions as classified in NCERT Exemplar

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) — (e);  (ii) — (d);  (iii) — (a);  (iv) — (b);  (v) — (f); (vi) — (c)

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) →  (c); (ii) →  (d); (iii) →  (a); (iv) →  (b).

This is a Matching Type Questions as classified in NCERT Exemplar

Ans: (i) →  (b); (ii) →  (e); (iii) →  (d); (iv) →  (a); (v) →  (c)

This is a Matching Type Questions as classified in NCERT Exemplar

 Ans: (i) →  (d); (ii) →  (e); (iii) →  (a); (iv) →  (b); (v) →  (c)

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: D

The silver mirror test can be used to determine Tollen's. [Ag (NH₃)₂] + OH ^- . Only aldehydes, not ketones, react with Tollen's reagent to create silver.

A silver mirror test is not given with this affirmative test.

The carbonyl group is present in both aldehyde and ketone.

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: C

There is no alpha hydrogen atom in the Cannizaro process. Formaldehyde and aromatic aldehydes do not contain alpha hydrogen. It proceeds through the Cannizaro reaction. Formaldehyde is the most reactive of all aldehydes.

This is a Assertion and Reason Type Questions as classified in NCERT Exemplar

Ans: D

Because of the presence of electron withdrawing carbonyl groups, the alpha hydrogen atom in carbonyl compounds is acidic. In nature, hydrogen is very acidic.

Because the cation is released in the form of H⁺ , the anion created after the loss of the -hydrogen atom is resonance stabilised.