Ncert Solutions Chemistry Class 12th
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New answer posted
6 months agoContributor-Level 10
11.11. Set (ii) is appropriate Because CH3Br is only a nucleophile whereas CH3ONa is nucleophile as well as strong base, so the elimination reaction can occur
New answer posted
6 months agoContributor-Level 10
11.10 During Williamson synthesis of ethers, an alkyl halide reacts with an alkoxide (ion with –ve charge on the oxygen of alcohol and + ve charge on alkali metal like Na) ion. it is an SN2 reaction. In the reaction, alkyl halides should be least hindered. Hence, an alkyl halide is obtained from ethanol and alkoxide ion from 3-methylpentan-2-ol. The reactions are shown below:
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6 months agoContributor-Level 10
11.9 Phenol on mixing with chloroform and NaOH at 340K followed by Acidic hydrolysis, salicyl aldehyde is formed. When carbon tetrachloride (CCl4) is used at the place of chloroform salicylic acid is This type of reaction is known as Reimer - Tiemann reaction.
2. The sodium phenoxide reacts with CO2 under pressure 4-7 atm at a 400K temperature to form sodium salicylate, which on acidification yields salicylic acid. This type of reaction is known as Kolbe's
New answer posted
6 months agoContributor-Level 10
11.8
Resonating structures of o-nitrophenoxide ions that are formed by the loss of a proton from o-nitrophenol are as follows:
Resonating structures of p-nitrophenoxide ions that are formed by the loss of a proton from p- nitrophenol are as follows:
Resonating structures of phenoxide ions that are formed by the loss of a proton from phenol are as follows:
It is clearly evident from the above structures that due to —R-effect of— NO2NO2 group, o-and p-nitrophenoxide ions are more stable than phenoxide ions. Consequently, o- and p- nitrophenols are more acidic than phenols.
New question posted
6 months agoNew answer posted
6 months agoContributor-Level 10
(a) (i) Primary alcohols do no react appreciably with Lucas' reagent (HCl –ZnCl2) at room temperature.
(ii) Tertiary alcohol reacts immediately with Lucas 'reagent.
New answer posted
6 months agoContributor-Level 10
11.5 In this reaction, when propene reacts with the given reagent then the double bond of propene breaks down with charges on them. So, H+ gets placed on the carbon which already has two hydrogen atom and OH- gets substituted on center carbon because it has the more positive charge which attracts OH-. Thus we get propene-2-or as a
2. In this reaction, when Methyl ( 2-oxocyclohexyl) ethanoate reacts with the given reagent then the double bond between the oxygen atom and cyclohexyl gets breaks down, such that O has a negative charge and that particular carbon will have a positive charge on it. So, to neutralize it, H+ gets substitut
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6 months agoContributor-Level 10
11.4 In the Grignard reagent reaction, the first step of the reaction is the nucleophilic addition of Grignard reagent to the carbonyl group to form an adduct, Hydrolysis of adduct results in the formation of alcohol.
Here, is the general reaction with Grignard reagent below:-
From here, it is clear that HCHO gives CH2OH groups, so R of Grignard reagent is the remaining part of given alcohols. Thus, select the suitable Grignard reagent by substituting the value of R. Now we can see the reaction given below:-
Methanal reacts with iso-propyl magnesium bromide, in presence of dry ether gives an additional compound. And this additional compou
New answer posted
6 months agoContributor-Level 10
11.3 (i) 3-chloroethyl-2-isopropylpentan-1-ol
(ii) 2,5-Dimethylhexane-1,3-diol
(iv) 3-Bromocyclohexanol
(v) Hex-1-en-3-ol
(vi) 2-Bromo-3-methylbut-2-en-1-ol
New answer posted
6 months agoContributor-Level 10
11.2 Allylic alcohol is an organic compound which has the structural formula CH2 = CHCH2OH. In other words, in these alcohols, the-OH group is attached to sp2 hybridized carbon next to the carbon-carbon double bond, that is to an allylic carbon. Therefore, in the above examples, the following are the allylic alcohols.
(ii) H2C = CH – CH2OH and
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