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Ncert Solutions Chemistry Class 12th

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Ncert Solutions Chemistry Class 12th Class 12th

Among the following allotropic forms of sulphur, the number of allotropic forms, which will show paramagnetism is…………………….

(a) α - sulphur (b) β - sulphur (c) S₂ - form

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Vishal Baghel

Contributor-Level 10

α - sulphur & β - sulphur – Diamagnetic, S₂ – form is paramagnetic due to presence of unpaired electron in π* orbital like O₂.

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Ncert Solutions Chemistry Class 12th Chemical Thermodynamics

Assuming ideal behaviour, the magnitude of log K for the following reaction at 25°C is x * 10^-1. The value of x is ………………… (integer answer)

3HC $\equiv C H_{(g)} ? C_{6} H_{6 (I)}$

[Given : $Δ_{f} G ° (H C \equiv C H)$ = -2.04 * 10⁵J mol^-1 ; $Δ_{f} G ° (C_{6} H_{6}) = - 1.24 * 1 0^{5} J m o l^{- 1} :$ R = 8.314 JK^-1mol^-1]

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Vishal Baghel

Contributor-Level 10

$3 C H \equiv C H (g) \to C_{6} H_{6} (l)$

$Δ G^{0} = - R T l n K . . . . . . . . . (i)$

$Δ G^{0} = \sum Δ {G^{0}}_{P} - \sum Δ {G^{0}}_{R} . . . . . . . . . . (i i)$

Equating (i) & (ii)

-2.303 RTlogk = 4.88 * 10⁵

$l o g K = \frac{- 4.88 * 1 0^{5}}{2.303 * R * T} = \frac{- 488000}{5705.848} = - 85.52 = - 855 * 1 0^{- 1}$

So; magnitude of log K = 855 * 10^-1

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Ncert Solutions Chemistry Class 12th Class 12th

1.86g of aniline completely reacts to form acetanilide. 10% of the product is lost during purification. Amount of acetanilide obtained after purification (in g) is………………….* 10^-2.

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Vishal Baghel

Contributor-Level 10

$\frac{1.86}{93} = \frac{w}{135}$

W = 2.70 g

Mass produced actual = 2.70 $* \frac{90}{100} = 2.43 = 243 * 1 0^{- 2} g$

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Ncert Solutions Chemistry Class 12th Class 12th

The solubility product of Pbl₂ is 8.0 * 10^-⁹. The solubility of lead iodide in 0.1 molar solution of lead nitrate is x * 10^-⁶ mol/L. The value of x is…………………… (Rounded off to the nearest integer)

[Given $\sqrt[]{2} = 1.41]$

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Vishal Baghel

Contributor-Level 10

$P b l_{2} ? P b^{2 +} + 2 l^{-} K_{s q} = 8.0 * 1 0^{- 9}$

Pb (NO₃)₂ -> Pb²⁺ +^{$2 N O_{3}^{-}$}

0.1 M-

-0.1 M 0.1 M

$K_{s q} = 8 * 1 0^{- 9} U s i n g K_{s q} = [P b^{2 +}] {[I^{-}]}^{2}$

$8 * 1 0^{- 9} = 0.1 * {(2 S)}^{2}$

S = 141 * 10^-6 M

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Ncert Solutions Chemistry Class 12th Class 12th

Sucrose hydrolyses in acid solution into glucose and fructose following first order rate law with a half – life of 3.33 h at 25°C. After 9h, the fraction of sucrose remaining is f. The value of log₁₀ $(\frac{1}{f})$ is………………….* 10^-². (Rounded off to the nearest integer)

[Assume: In 10 = 2.303, In2 = 0.693]

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Vishal Baghel

Contributor-Level 10

$C_{12} H_{22} O_{11} + H_{2} O \to \underset{G l u c o s e}{C_{6} H_{12} O_{6}} + \underset{F r u c t o s e}{C_{6} H_{12} O_{6}}$

$K = \frac{2.303}{t} l o g \frac{a}{a - x}$

$\frac{k t}{2.303} = l o g \frac{a}{a - x}$

$\frac{l n 2 * 9}{\frac{10}{3} * 2.303} = l o g (\frac{1}{f})$

$l o g (\frac{1}{f}) = 81.24 * 1 0^{- 2} = 81 * 1 0^{- 2}$

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Ncert Solutions Chemistry Class 12th Class 12th

The total number of amines among the following which can be synthesized by Gabriel synthesis is………………

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Vishal Baghel

Contributor-Level 10

Gabriel phthalimide synthesis is used for 1° Aliphatic /alicyclic amine

1° Amine

CH₃ – CH₂ – NH₂

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Ncert Solutions Chemistry Class 12th Class 12th

Which of the following reagent is suitable for the preparation of the product in the above reaction?

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Ncert Solutions Chemistry Class 12th Class 12th

The correct order of the following compounds showing increasing tendency towards nucleophilic substitution reaction is:

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Vishal Baghel

Contributor-Level 10

If we add -NO₂ group on ortho and para position, then electron deficiency increasing in benzene ring so, order of nucleophilic attack is

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Ncert Solutions Chemistry Class 12th Environmental chemistry

Given below are two statements:

Statement I : The value of the parameter “Biochemical Oxygen Demand (BOD)” is important for survival of aquatic life.

Statement II : The optimum value of BOD is 6.5 ppm.

In the light of the above statements, choose the most appropriate answer from the options given below:

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Vishal Baghel

Contributor-Level 10

Clean water would have BOD Value less than 5ppm, highly polluted water could have BOD value of 17 ppm or more.

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Ncert Solutions Chemistry Class 12th Class 12th

The diazonium salt of which of the following compounds will form a coloured dye on reaction with β-Naphthol in NaOH?

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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