Ncert Solutions Chemistry Class 12th

Depression in freezing point will be maximum for Al₂ (SO₄)₃ since its Van't Hoff factor is the highest. So its solution will have the lowest freezing point.

When AgNO₃ is added to Kl solution, precipitate of Agl is formed which adsorb I^- ion from

Dispersion medium to give negatively charged sol

$AgN{O}_3+Kl\to Agl\downarrow +KN{O}_3$

Agl/l^-- negatively charged sol.

Esters on treating with excess CH₃MgBr followed by hydrolysis gives 3° alcohol.

 

Reaction of acetone and semicarbazide

Hence, electronic configuration of CO²⁺ is $\left[Ar\right]3d^{7}4s^0$ . In complex ${\left[Co{\left(CN\right)}_6\right]}^{4-},$ given ligand CN^- is $\therefore$ strong hence, after pairing in d-subshell, total number of unpaired electron =

spin magnetic moment = $\sqrt[]{1\left(1+2\right)}=\sqrt[]{3}=1.73BM$ $=1.73BM\approx 2.0BM$  

Both statement are correct for the glass body heating, but reason is not correct explanation during heating process of glass, constituents unit rupture of glass body and gives the edge smoothness.

All structure can produce -CHO functional group which gives +ve test of Tollen's reagent except structure (II), because if forms ketonic group after tautomerisation

$X\underset{H_{2}S{O}_4}{\overset{Conc}{\to }}$ Brown fumes + Brown ring test with FeSO₄/H₂SO₄

$x\underset{HCl}{\overset{H_{2}S}{\to }}Y\left(ppt\right)\underset{HN{O}_3}{\overset{Conc}{\to }}dissolved\underset{N{H}_{4}OH}{\overset{}{\to }}$ Deep blue colour solution

In cation analysis of Cu⁺ ions, precipitate formed is CuS on treating with H₂S and HCl which dissolved in HNO₃ and produced blue colour complex solution ${\left[Cu{\left(N{H}_3\right)}_4\right]}^{++}$ in NH₄OH. Brown fumes and brown ring performance given by nitrate sample. Hence salt is Cu (NO₃)₂.

In $Br{O}_4^{-},Br$ has +7 O.S, therefore it only acts as a oxidizing reagent, does not undergo disproportionation reaction