Ncert Solutions Chemistry Class 12th

Indium and other semi conducting materials behaves different characteristic of impurities and pure particle at high temperature zone. Hence in metallurgical process it is refined by the zone refining.

Buna-S required nascent oxygen

Butadiene + styrene $\underset{}{\overset{\left[0\right]}{\to }}$ (Buna-S)

Conversion form

Viscosity of the hydrophilic sol is always higher than H₂O, because dispersed phase particle attracted by dispersion medium.

$logK=logA-\frac{Ea}{2.303RT}$

$Slope=\frac{Ea}{2.303R}=-10,000K$  

$\frac{Ea}{2.303R}=10^4$            

$log\left(10^{-5}\right)=logA-10^4*\frac{1}{500}$   (at 500 K temperature)

$\therefore T=\frac{10^4}{19}K=\frac{100}{19}*10^{2}K=5.2631*10^{2}K=526.31K\approx 526K$

(1) 4 mol of $=4{}_A$ atoms

(2) 4 u of $=\frac{4u}{4u}=1$ atom

(3) 4 g of Helium $=\frac{4}{4}$ mole $=1$ mole $=N_A$ He atom

(4) $2.2710982$ of He at STP $=\frac{2.271}{22.710982}$ mole

$=0.1$

$=0.1{}_A$

Nucleophilic addition of sodium hydrogen sulphite to aldehyde or ketone is a;

$NaHS{O}_3?N{a}^{+}+HS{O}_3^{?}$                

So; nucleopilic addition of sodium hydrogen sulphite to an aldehyde or a ketone involves proton transfer to form a stable ion.

Addition of hydrogen cyanide;

Final product is cyanohydrin.

All given oxide have nitrogen – nitrogen bond except N₂O₅ as ;

Here, C₃H₆ is propene

Second reaction is iodoform reaction.