Ncert Solutions Maths class 12th

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New answer posted•a year ago
S
a year ago

A: runner succeeded exactly 3 times out of 5.
B: runner succeeds on the first trial.
P (B/A) = P (B ∩ A) / P (A) = (p (? C? p² (1−p)²) / (? C? p³ (1-p)²) = 3/5 = 0.6

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New answer posted•a year ago
S
a year ago

Volume = |a b c; b c a; c a b| = |3abc – a³ – b³ – c³|
= | (a + b + c) (a² + b² + c² – ab – bc – ca)| = | (a + b + c) (a + b + c)² – 3 (ab + bc + ca)|
= |9 (81-3 × 15)| = 324

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New answer posted•a year ago
S
a year ago

  ( λ , 2 λ , 3 λ )

c o s θ = 6 4 2 ⇒ s i n θ = 6 4 2 (where q is the angle between L1 & L2)

A r e a     Δ O A B = 1 2 ( O A ) ( O B ) s i n θ

= 1 2 ( 3 ) | λ | ( 1 4 ) 6 4 2 = 6 ⇒ λ = ± 2

            

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

k = [ a →     b →     c → ] + 2 [ a →     b →     c → ] + [ a →     b →     c → ] − [ a →     b →     c → ] [ a →     b →     c → ]            

k = 3

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New answer posted•a year ago
S
a year ago

l i m x → 0 [ s i n 2 ( π 2 − 3 x ) ] s e c 2 ( π 2 − 5 x )

e l i m x → 0 [ s i n 2 ( π 2 − 3 x ) − 1 ] s e c 2 ( π 2 − 5 x )

= e l i m x → 0 − s i n 2 ( − 3 π x 2 ( 2 − 3 x ) ) s i n 2 ( − 5 π x 2 ( 2 − 5 x ) ) = e − 9 2 5

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New answer posted•a year ago
S
a year ago

For point of intersection
1 + 3λ = 3 + μ
2 + λ = 1 + 2μ
5λ = 5 ⇒ λ = 1, μ = 1
Point of intersection (4, 3, 5)
For the greatest distance from origin perpendicular from meet plane at point of intersection
Hence equation r . (4i + 3j + 5k) = 50

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New answer posted•a year ago
S
a year ago

∫ − a a ( | x | + | x − 2 | ) d x = 2 2 , a > 2

∫ − a 0 ( − 2 x + 2 ) d x + ∫ 0 2 ( x − x + 2 ) d x + ∫ 2 a ( 2 x − 2 ) d x = 2 2

⇒ 2 a 2 + 2 = 2 0 ⇒ a 2 = 9 ⇒ a = 3

∴ ∫ 3 − 3 ( x + [ x ] ) d x = − ∫ − 3 3 ( 2 x − { x } ) d x = − ∫ − 3 3 2 x d x + 6 ∫ 0 1 x d x = 6 . x 2 2 | 0 1 = 3           

            

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New answer posted•a year ago
New answer posted•a year ago