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New answer posted

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Req = r

P = V 2 r = 4 2 = 2 W

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

p = i2R

P' = 0.64 i2R

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

i = neAVd

 

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

01 * 104 Ω ± 5% = 10 * 103 Ω ± 5%

New answer posted

2 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

When wire is stretched uniformly

R R

R R ' = l n l 2 = 1 n 2  

R ' = n 2 R

When this elongated wire is cut into 5 parts, resistance of each part  

Effective resistance between A and C = n 2 R 5  

New answer posted

2 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Resistance of whole wire is

R = r ' * l

20 = 1 * l

l = 20 m

Let length of the shorter section = a

1 R = 1 a + 1 20 - a

1 1.8 = 20 - a + a a 20 - a ? 20 a - a 2 = 36

a = 2 a n d 18

? a = 2 m

New answer posted

2 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

(Explanation can be elaborate)

l = 25 R e q
R e q = 25 Ω
l = 25 25 1 A

 

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