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New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

? s B ? d A ? = 0 (No monopole exist)

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

R = 22 * 10 3 ± 5 % First band  Red

2nd band =  Red

3rd band =Orange (Multiplier)

4th band = Gold (Tolerance)

New answer posted

a month ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

R_eq = (R? )/ (R? +R? ) ⇒ p (l)/ (2A) = [ (p? l/A) (p? l/A)] / [ (p? l/A) + (p? l/A)]

⇒ ρ/2 = (p? )/ (p? +p? ) ⇒ ρ = (2p? p? )/ (p? +p? ) = (2 * 6 * 3)/9 = 4 Ωcm

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

12/x = 6/ (72-x) ⇒ x = 144 - 2x ⇒ x = 144/3 = 48cm

New answer posted

a month ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Conduction current density, J? = E/ρ = (V/d) / ρ = (V? sin (2πft) / (pd)
Displacement current density, J? = ε (dE/dt) = (ε/d) (dV/dt) = (2πfε/d) * V? cos (2πft)
The ratio of their magnitudes is:
J? / J? = tan (2πft) / (2πfε? ρ) = tan (2π * 900) / (2π * 9 * 10? * 80ε? * 0.25) = 10?

New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

For series combination: s = R? + R?

For parallel combination: p = (R? ) / (R? + R? )

Given the condition s = np:
R? + R? = n * (R? ) / (R? + R? )
(R? + R? )² = nR? R?
R? ² + 2R? R? + R? ² = nR? R?
R? ² - 2R? R? + R? ² + 4R? R? = nR? R?
(R? - R? )² = (n - 4)R?
(R? - R? )² / (R? ) = n - 4
n = 4 + (R? - R? )² / (R? )

Since (R? - R? )² is always non-negative, the minimum value of the term (R? - R? )² / (R? ) is 0. This occurs when R? = R?
Therefore, the minimum value of n is 4.

New answer posted

a month ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Given:

  • i = 10
  • e = 1.6 x 10? ¹? C
  • A = 5 x 10?
  • V = 2 x 10? ³

The formula for current is I = neAV.
Rearranging for n (number of free electrons per unit volume):
n = I / (eAV)
n = 10 / (1.6 * 10? ¹? * 5 * 10? * 2 * 10? ³)
n = 625 * 10²?

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

i? = 40/100 = 2/5
i? = 40/200 = 1/5
V? – V? = 40i? = 40 * 2/5
V? – V? = 16
V? – Vd = 90i? = 90/5 = 18
V? – Vd = 18 – 16 = 2 volt

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

In Ohm's law experiment, ammeter is used in series because in series same current will flow through it. But voltmeter is used in parallel to resistor to measure the potential difference across it.

 

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