Physics Mechanical Properties of Fluids
Get insights from 89 questions on Physics Mechanical Properties of Fluids, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics Mechanical Properties of Fluids
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
4 weeks agoContributor-Level 10
Mass

Density of ball
Density of glycerine
For constant velocity,
New answer posted
4 weeks agoContributor-Level 9
Initially speed is zero, then increases & after some time it becomes constant.
New question posted
4 weeks agoNew answer posted
4 weeks agoContributor-Level 10
v? ²/2 + P? /ρ + gh? = v? ²/2 + P? /ρ + gh?
⇒ v? ²/2 + (P? + ρgh + mg/A)/ρ + g * 0 = v? ²/2 + P? /ρ + g * 0
⇒ v? ²/2 + (ρgh + mg/A)/ρ = v? ²/2 . (1)
Using Continuity equation, we can write
Av? = av? ⇒ v? = (a/A)v?
Putting the value of v? in equation (1), we have
(a²/A²)v? ²/2 + (ρgh + mg/A)/ρ = v? ²/2 ⇒ (A² - a²)/A² * v? ²/2 = (ρgh + mg/A)/ρ
⇒ v? = √ [ (A²/ (A²-a²) * 2 (ρgh + mg/A)/ρ] = 3.09 m/s ≈ 3 m/s
New answer posted
a month agoContributor-Level 10
P? - P? = 4T/a
P? - P? = 4T/b
P? - P? = 4T (1/a - 1/b)
Also, P? - P? = 4T/r
4T/r = 4T (1/a - 1/b)
1/r = (b-a)/ab
r = ab / (b-a)
New answer posted
a month agoContributor-Level 10
B (ΔV/V) = ΔP
ΔV/V = ΔP/B = (4 x 10? )/ (8 x 10¹? ) = 1/20
V = l³
dV = 3l² dl
dV/V = 3l²dl/l³ = 3dl/l
ΔV/V = 3 (Δl/l); 1/20 = 3 (Δl/l); ΔV/V = 1/60
% (Δl/l) = 100/60 = 1.67%
New answer posted
a month agoContributor-Level 10
Using Bernoulli's equation
P? + (1/2)ρv? ² + ρgh? = P? + (1/2)ρv? ² + ρgh?
For horizontal tube h? = h?
P + (1/2)ρv² = P/2 + (1/2)ρV²
(1/2)ρV² = P/2 + (1/2)ρv²
V = √ (P/ρ + v²)
New answer posted
a month agoContributor-Level 10
sx? dg (x? /2) + sx? dg (x? /2)
Uf = (S (x? +x? )/2)gd (x? +x? )/4) x 2
= S (x? + x? )²gd/4
U? -Uf = (Sgd/4) {2x? ² + 2x? ² − (x? + x? )²}
= (Sgd/4) (x? -x? )²
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers