Physics Mechanical Properties of Fluids

Get insights from 89 questions on Physics Mechanical Properties of Fluids, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics Mechanical Properties of Fluids

Follow Ask Question
89

Questions

0

Discussions

5

Active Users

0

Followers

New answer posted

4 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Mass = M

Density of ball = d

Density of glycerine = d 2

F B = V s ρ l g = V d 2 g

F g = M g = v d g

For constant velocity, F net   = 0

F B + F v = M g

F V = M g - F B = V d g - V d g 2 = V d g 2 = M g 2

 

New answer posted

4 weeks ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

P = P 0 + 4 T R

on expansion R increase, as a result, P  decreases.

New answer posted

4 weeks ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Initially speed is zero, then increases & after some time it becomes constant.

New answer posted

4 weeks ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

η = 1 - T sin   k T source   = 0.5

T sin   T source   = 0.5 T sin   = 1 2 * ( 273 + 327 ) = 1 2 * 600 = 300 K = 27 ? C

New question posted

4 weeks ago

0 Follower 3 Views

New answer posted

4 weeks ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

v? ²/2 + P? /ρ + gh? = v? ²/2 + P? /ρ + gh?

⇒ v? ²/2 + (P? + ρgh + mg/A)/ρ + g * 0 = v? ²/2 + P? /ρ + g * 0

⇒ v? ²/2 + (ρgh + mg/A)/ρ = v? ²/2 . (1)

Using Continuity equation, we can write
Av? = av? ⇒ v? = (a/A)v?

Putting the value of v? in equation (1), we have
(a²/A²)v? ²/2 + (ρgh + mg/A)/ρ = v? ²/2 ⇒ (A² - a²)/A² * v? ²/2 = (ρgh + mg/A)/ρ

⇒ v? = √ [ (A²/ (A²-a²) * 2 (ρgh + mg/A)/ρ] = 3.09 m/s ≈ 3 m/s

New answer posted

a month ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

P? - P? = 4T/a

P? - P? = 4T/b

P? - P? = 4T (1/a - 1/b)

Also, P? - P? = 4T/r

4T/r = 4T (1/a - 1/b)

1/r = (b-a)/ab

r = ab / (b-a)

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

B (ΔV/V) = ΔP
ΔV/V = ΔP/B = (4 x 10? )/ (8 x 10¹? ) = 1/20
V = l³
dV = 3l² dl
dV/V = 3l²dl/l³ = 3dl/l
ΔV/V = 3 (Δl/l); 1/20 = 3 (Δl/l); ΔV/V = 1/60

% (Δl/l) = 100/60 = 1.67%

New answer posted

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Using Bernoulli's equation
P? + (1/2)ρv? ² + ρgh? = P? + (1/2)ρv? ² + ρgh?
For horizontal tube h? = h?
P + (1/2)ρv² = P/2 + (1/2)ρV²
(1/2)ρV² = P/2 + (1/2)ρv²
V = √ (P/ρ + v²)

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

sx? dg (x? /2) + sx? dg (x? /2)
Uf = (S (x? +x? )/2)gd (x? +x? )/4) x 2
= S (x? + x? )²gd/4
U? -Uf = (Sgd/4) {2x? ² + 2x? ² − (x? + x? )²}
= (Sgd/4) (x? -x? )²

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 688k Reviews
  • 1800k Answers

Share Your College Life Experience

×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.