Physics Mechanical Properties of Fluids

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A
alok kumar singh

Contributor-Level 10

k x = m g - F u p

k x = m g - m d D g

x = m g k 1 - d D

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2 weeks ago

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A
alok kumar singh

Contributor-Level 10

Since the water removed from the pond will be equal to the water displacement by the (man + boat) system, the level of water in the pond remains the same.

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R
Raj Pandey

Contributor-Level 9

R = n 1 / 3 r

E=T.ΔA=msΔTJ

 

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Raj Pandey

Contributor-Level 9

Water level in both section A and B will be goes up due being of centrifugal force water will goes away and it acquire the force from upside so the water will does up so water level in both the section A and B goes up.

New answer posted

2 weeks ago

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A
alok kumar singh

Contributor-Level 10

k x = m g - F u p

k x = m g - m d D g

x = m g k 1 - d D

New answer posted

2 weeks ago

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V
Vishal Baghel

Contributor-Level 10

v T r 2

v T 1 v T 2 = r 1 2 r 2 2 = r 2 9 r 2

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V
Vishal Baghel

Contributor-Level 10

Applying Bernoulli's theorem

P 0 + ρ g 2 h + 2 ρ g h + 0 = P 0 + 1 2 2 ρ v 2

V 2 = 4 g h

v = 2 g h

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A
alok kumar singh

Contributor-Level 10

Cohesive force in mercury molecules are greater than adhesive force

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R
Raj Pandey

Contributor-Level 9

ρ = 8 0 0 k g / m 3

P1 – P2 = 4100 Pa

 Bernoulli's question b/w (1) & (2)

P 1 ρ g + v 1 2 2 g + z 1 = P 2 ρ g + v 2 2 2 g + z 2  

⇒  P 1 P 2 ρ g + v 1 2 2 g + 1 = v 2 2 2 g + 0            -(1)

Equation of continuity

A1v1 = A2v2

v2 = 2v1                -(2)

from (1) & (2)

P 1 P 2 ρ g + v 1 2 2 g + 1 = ( 2 v 1 ) 2 2 g  

4 1 0 0 8 0 0 * 1 0 + v 1 2 2 g + 1 = 4 v 1 2 2 g  

1 2 1 0 0 8 0 0 0 = 3 v 1 2 2 g

v 1 2 = 2 * 1 0 3 * 1 2 1 0 0 8 0 0 0  

  = 2 3 * 1 2 1 8  

                 x = 363

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2 weeks ago

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V
Vishal Baghel

Contributor-Level 10

Since velocity does not change, so acceleration will be zero.

mg = FB + Fv 4 π 3 r 3 ρ g = 4 π 3 r 3 σ g + 6 π η r v

v = 2 r 2 ( ρ σ ) g 9 η = 2 * 0 . 1 * 0 . 1 * 1 0 6 * ( 1 0 4 1 0 3 ) * 1 0 9 * 1 . 0 * 1 0 5

h = 4 0 0 2 g = 2 0 m

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