Physics Mechanical Properties of Solids

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New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

The bulk modulus B is calculated as:
B = -ΔP / (ΔV/V) = (ρgh) / (ΔV/V) = (10³ * 9.8 * 2 * 10³) / (1.36 * 10? ²) = 1.44 * 10? N/m²

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

As it just floats B = mg
(4πR³/3) (ρ‎? ) (g) = (4πR³/3 - 4πr³/3) (ρ‎? ) (g)
R³ = (R³ - r³) (27/8)
On solving we get,
r = 8/9 R (approx)

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

B (ΔV/V) = ΔP
ΔV/V = ΔP/B = (4 x 10? )/ (8 x 10¹? ) = 1/20
V = l³
dV = 3l² dl
dV/V = 3l²dl/l³ = 3dl/l
ΔV/V = 3 (Δl/l); 1/20 = 3 (Δl/l); ΔV/V = 1/60

% (Δl/l) = 100/60 = 1.67%

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

  v = T μ

T = μ v 2 μ v 2 A = Y Δ l l

after substituting value of Δ l = μ v 2 l A Y  and μ , v , l , A  we get

Y

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

Loss in elastic potential energy = Gain in KE
½ (YA/L)x² = ½mv²
0.5 * (0.5*10? * 10? / 0.1) * (0.04)² = 20*10? ³ v²
0.5 * (5*10²) * 1.6*10? ³ = 20*10? ³ v²
0.4 = 20*10? ³ v²
v² = 20 => v = √20 ≈ 4.47 m/s
(Re-checking calculations)
0.5 * ( (0.5e9 * 1e-6) / 0.1) * (0.04)^2 = 0.5 * (5e2) * 1.6e-3 = 4.
0.5 * 20e-3 * v^2 = 10e-3 v^2
4 = 10e-3 v^2
v^2 = 400 => v = 20 m/s

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Y? = (F/A) / (Δl? /l)
Y? = (F/A) / (Δl? /l)
Y = (F/A) / (Δl? + Δl? )/ (2l)
= (F/A) / ( (1/2) * (Δl? /l + Δl? /l) )
= (F/A) / ( (1/2) * (F/ (AY? ) + F/ (AY? ) )
= 2Y? Y? / (Y? + Y? )

 

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

If   μ is Poisson's ratio,

Y = 3K (1 - 2 μ )      ……… (1)

and Y = 2 n ( 1 + μ )   ……… (2)

With the help of equations (1) and (2), we can write

3 Y = 1 η + 1 3 k K = η Y 9 η 3 Y      

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

From defined of bulk modulus

K=P (dV/V)....... (1)

m = ρv=constant

ρdV+Vdρ=0

dVV=dρρ......... (2)

With the help of equations (1) and (2), we can write

K=P (dρρ)=ρPdρdρ=ρPK

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