Physics Mechanical Properties of Solids
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New answer posted
a month agoContributor-Level 10
The bulk modulus B is calculated as:
B = -ΔP / (ΔV/V) = (ρgh) / (ΔV/V) = (10³ * 9.8 * 2 * 10³) / (1.36 * 10? ²) = 1.44 * 10? N/m²
New answer posted
a month agoContributor-Level 10
As it just floats B = mg
(4πR³/3) (ρ? ) (g) = (4πR³/3 - 4πr³/3) (ρ? ) (g)
R³ = (R³ - r³) (27/8)
On solving we get,
r = 8/9 R (approx)
New answer posted
a month agoContributor-Level 10
B (ΔV/V) = ΔP
ΔV/V = ΔP/B = (4 x 10? )/ (8 x 10¹? ) = 1/20
V = l³
dV = 3l² dl
dV/V = 3l²dl/l³ = 3dl/l
ΔV/V = 3 (Δl/l); 1/20 = 3 (Δl/l); ΔV/V = 1/60
% (Δl/l) = 100/60 = 1.67%
New answer posted
a month agoContributor-Level 10
Loss in elastic potential energy = Gain in KE
½ (YA/L)x² = ½mv²
0.5 * (0.5*10? * 10? / 0.1) * (0.04)² = 20*10? ³ v²
0.5 * (5*10²) * 1.6*10? ³ = 20*10? ³ v²
0.4 = 20*10? ³ v²
v² = 20 => v = √20 ≈ 4.47 m/s
(Re-checking calculations)
0.5 * ( (0.5e9 * 1e-6) / 0.1) * (0.04)^2 = 0.5 * (5e2) * 1.6e-3 = 4.
0.5 * 20e-3 * v^2 = 10e-3 v^2
4 = 10e-3 v^2
v^2 = 400 => v = 20 m/s
New answer posted
a month agoContributor-Level 9
Y? = (F/A) / (Δl? /l)
Y? = (F/A) / (Δl? /l)
Y = (F/A) / (Δl? + Δl? )/ (2l)
= (F/A) / ( (1/2) * (Δl? /l + Δl? /l) )
= (F/A) / ( (1/2) * (F/ (AY? ) + F/ (AY? ) )
= 2Y? Y? / (Y? + Y? )
New answer posted
a month agoContributor-Level 10
If
Y = 3K (1 - 2
and Y = 2
With the help of equations (1) and (2), we can write
New answer posted
a month agoContributor-Level 10
From defined of bulk modulus
m =
With the help of equations (1) and (2), we can write
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