physics ncert exemplar solution class 12th chapter one

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a week ago

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R
Raj Pandey

Contributor-Level 9

Let V  be the potential of the junction as shown in figure. Applying junction law, we have

or 2 0 V 2 + 5 V 4 ¯ V 0 2

or 4 0 2 V + 5 V = 2 V or 5 V = 4 5 V = 9 V

  i 3 = V 2 = 4 . 5 A

New answer posted

a week ago

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R
Raj Pandey

Contributor-Level 9

Please consider the following Image  

 

New answer posted

a week ago

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R
Raj Pandey

Contributor-Level 9

Before closing the switch

After closing the switch

So charge on C1  remains same, on C2 increases and on C3 and C4  decreases.

New answer posted

2 months ago

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P
Payal Gupta

Contributor-Level 10

Decay of current in Inductor is given by,

i=i0et/τ[Whereτ=LR;i0=vR=2010=2]

At t = 100 μs

i = 0

i.e. i = i0 e100/τ=0 -(1)

e.m.f induced

e=Ldidt=Lddt[i0et/τ]

=Li012et/τ

e=Li0τet/τ

eavg=0200μsedt0200μsdt=0200μsLi0τet/τdt0200μsdt

=Li0200*106sec=20*103*2200*106=400

New answer posted

2 months ago

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P
Payal Gupta

Contributor-Level 10

If size of object is very small as compare to wave length of EM wave in free space then, scattering will happen.

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2 months ago

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A
alok kumar singh

Contributor-Level 10

F1=9*109*5*106*0.3*1069*104

= 15 N

F2=9*109*5*106*0.16*1069*104

= 8N

Fnet= (15)2+ (8)2

= 17 N

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2 months ago

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P
Payal Gupta

Contributor-Level 10

All the charge given to a conducting sphere resides on outer surface.

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2 months ago

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P
Payal Gupta

Contributor-Level 10

N=mgcos30°+qEsin30°

a=mgsinθqEcosθμNm=2.30m/s2

S=ut+12at2

t=2la=1.31sec

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

 Electric field due to infinite sheet is uniform.

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

 E=8mev/m

Time to come out, t = 12sec

Vy=at= (eEm)t= (em*8me)*12=4m/s

So,  tan? =VyVx=42

? ? =tan? 12

 

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