Physics NCERT Exemplar Solutions Class 11th Chapter Eleven

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) density = mass/volume as density is same so volume is also same.

According to Stefan's law H AT4  where A is the area and T is the temperature

Hsphere:Hcube:Hplate= Asphere:Acube:Aplate

As Aplate is maximum.

Hence the plate will cool the fastest.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(d) Let radius of sphere be R . as the temperature increases radius of the sphere increases.

Original volume Vo= 4 3 π R 3

Coefficient linear expansion = α

Coefficient of volume expansion =3 α

d V V d T = 3 α  , dV= 4 π R3  α ? T =increase in volume

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Payal Gupta

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(a) We know that temperature increases vibrations of molecules about their mean position increases. Hence kinetic energy associated with random motion of molecules increases.

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Payal Gupta

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This is a multiple choice answer as classified in NCERT Exemplar

As the temperature is increased length of the pendulum increases.

T=2 π L g

So if we increase L then T also increases.

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Payal Gupta

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(a) F= V ρ G

F ρ

F 4 0 C > F 0 0 C

Hence buoyancy will be less in water at 00C than that in water at 40C.

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Payal Gupta

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(b) Lowest point for scale A is 300 and lowest point for scale B is 00. Highest point for the scale A is 1800 and for scale B is 1000

t A - L E P A U F P A - L F P A = t B - L F P B U F P B - L F P B
t A - 30 180 - 30 = t B - 0 100 - 0

t A - 30 150 = t B 100 ,LFP= lower fixed point , UFP= upper fixed point ρ

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

L = angular momentum = Iw = constant

I1w1=I2w2

Due to expansion of the rod I2>I1

w 2 w 1 = I 1 I 2 1

w21 so angular velocity decreases.

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Payal Gupta

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(d) As  α A l > α s t e e l , aluminium will expand more . so it would have larger radius of curvature. So aluminium will expand and will outside region.

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Payal Gupta

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The first option kept water warmer because according to newton's law of cooling the rate of loss of heat is directly proportional to the difference of temperature of the body and the surroundings and in the first case temperature difference is less. So rate of loss of heat will be less.

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Payal Gupta

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This is a short answer type question as classified in NCERT Exemplar

Mass of water m =100

Change in temperature ? T = 0 10 = 10 ° C

Specific heat of water Sw= 1cal/g ° C

Latent heat of fusion of water Lfusion= 80cal/g

Heat required to bring water in super cooling from -10 to 0 ° C

Q= ms ? t = 100 * * 10 = 1000 c a l

Let m gram of ice be melted Q= mL

m=Q/L=1000/80= 12.5g

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