Physics Ncert Solutions Class 12th

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4 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

We have to transmit energy (power) over large distances at high alternating voltages, so current flowing through the wires will below because for a given power (P).

P= ErmsIrms, Irms  is low when Erms is high.

Power loss= I 2 rms R= low

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c, d) According to the question, the current increases on increasing the frequency of supply. Hence, the reactance of the circuit must be decreases as increasing frequency.

For a capacitive circuit,  capacitive reactance Xc= 12πϑC

For an CR circuit Z= R2+ (Xc2) when frequency increases X decreases.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(a, d) inductive reactance XL= 2 πϑ L

 
For an LCR circuit Z= R2+ (XL-XC) 2

As frequency (ν) increases, Z decreases and at certain value of frequency know as resonant frequency (ν0), impedance Z is minimum that is Zmin= R current varies inversely with impedance and at Zmin current is maximum.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Secondary voltage Vs= 24V

Power associated with secondary Ps = 12W

IsPSVS = 12/24= 0.5A

I0= Is 2 = 1/ 2 A

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

Average power dissipated is ErmsIrmscos

Z= R2+XL2

1+4 = 5

Irms= 6/ 5 A

cos  =R/Z=2/ 5

pav= 6 *65*25 = 14.4W

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4 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) As we know that Q= 1RLC to make Q high R should be low, L should be high and C should be low.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

As we know resonant frequency is v0= 12πLc

To increase capacitance we must connect it to another capacitor parallel to the first.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) The voltmeter connected to AC Mains reads mean value (2>) and is calibrated in such a way that it gives value of, which is multiplied by form factor to give rms value.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) For delivering maximum power from the generator to the load, total internal reactance must be equal to conjugate of total external reactance.

XL=-Xg

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(b) I02 Irms= 2  (5)A

I=I0sinwt = 5 2 sin π/3 = 5 32 A

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