Physics Oscillations

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New answer posted

3 months ago

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R
Raj Pandey

Contributor-Level 9

x = A s i n ω t   (Eq. of a particle executing SHM)

When KE = PE

1 2 m v 2 = 1 2 k x 2

1 2 m ω 2 ( A 2 x 2 ) = 1 2 k x 2 [ ? k = m ω 2 ]

A2 – x2 = x2

  S o , A 2 = A s i n ω t

1 2 = s i n ω t

t = T 8

New answer posted

3 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Velocity of bob after collision,

v1 = 5 g R = 5 * 1 0 * 0 . 5 = 5 m / s

From Conservation of Momentum,

1 0 1 0 0 0 * v = 1 0 1 0 0 0 * 1 0 0 + 1 * 5  

->v = 400 m/s  

 

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

λ 4 = l λ = 4 l

f = v λ = v 4 l l = v 4 f
l = 3 4 4 * 2 5 = 0 . 3 4 m = 3 4 c m

 

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Potential Energy is maximum at extreme position

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

x 1 = 5 s i n ( 2 π t + π 4 )

x 2 = 5 2 ( s i n 2 π t + c o s 2 π t )

= 1 0 s i n ( 2 π t + π 4 )

x 2 , m a x = 2 . x 1 , m a x

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

L e t , E m a g b T c

So, [ E ] = [ m ] a [ g ] b [ T ] c  

M L 2 T 2 = M a ( L T 2 ) b T c  

Thus, E = k mg2 T2

Δ E E = 2 . Δ g g + 2 . Δ T T   

Percentage error in E = 2 * 4 + 2 * 3 = 14%

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  Δ T T = 1 2 Δ l l

Δ T = 1 2 * 0 . 1 1 0 0 * 2 4 * 6 0 * 6 0 = 4 3 . 2 s            

             

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

x = A s i n ω t

Angle travelled by while moving from A to B

θ = 3 0 ° = π ° 6

θ = ω t

π 6 = ω * 3 [ t = 3 s e c ]

ω = π 1 8

T = 2 π ω = 2 π * 1 8 π = 3 6 s e c

T = 36 sec

 

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

T 1 = 2 π 3 m 2 k

T 2 = 2 π m 3 k

T 1 T 2 = 2 π 3 m 2 k 2 π m 3 k = 3 2

New answer posted

3 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

As we know that

gP=g (RR+h)2=g (RR+2R)2=g9, so

T=2πlgPl=gpT24π2=19m

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