Tags Physics Oscillations

Physics Oscillations

Get insights from 123 questions on Physics Oscillations, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics Oscillations

Follow Ask Question

123

Questions

Discussions

Active Users

Followers

New answer posted

6 months ago

Physics Oscillations Class 11th

A tuning fork is vibrating at 250 Hz. The length of the shortest closest organ pipe that will resonate with the tuning fork will be_____cm.

(Take speed of sound in air as 340 ms^-¹)

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

$\frac{λ}{4} = l \Rightarrow λ = 4 l$

f = \frac{v}{λ} = \frac{v}{4 l} \Rightarrow l = \frac{v}{4 f}

l = \frac{34}{4 * 25} = 0.34 m = 34 c m

0 0

New answer posted

6 months ago

Physics Oscillations Oscillations

The variation of displacement with time of a particle executing free simple harmonic moton is shown in the figure. The potential energy U(x) versus time (t) plot of the particle is correctly shown in figure:

0 Follower 7 Views

Vishal Baghel

Contributor-Level 10

Potential Energy is maximum at extreme position

0 0

New answer posted

6 months ago

Physics Oscillations Class 11th

Two simple harmonic motions are represented by the equations x₁ = 5 $s i n (2 π t + \frac{π}{4})$ and $x_{2} = 5 \sqrt[]{2} (s i n 2 π t + c o s 2 π t) .$ The amplitude of second motion is________ times the amplitude in first motion.

0 Follower 3 Views

alok kumar singh

Contributor-Level 10

$x_{1} = 5 s i n (2 π t + \frac{π}{4})$

$x_{2} = 5 \sqrt[]{2} (s i n 2 π t + c o s 2 π t)$

$= 10 s i n (2 π t + \frac{π}{4})$

$x_{2, m a x} = 2 . x_{1, m a x}$

0 0

New answer posted

6 months ago

Physics Oscillations Class 11th

The acceleration due to gravity is found upto an accuracy of 4% on a planet. The energy supplied to a simple pendulum of known mass 'm' to undertake oscillations of time period T is being estimated. If time period is measured to an accuracy of 3%, the accuracy to which E is known as_______%.

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

$L e t, E \propto m^{a} g^{b} T^{c}$

So, $[E] = {[m]}^{a} {[g]}^{b} {[T]}^{c}$

$\Rightarrow M L^{2} T^{- 2} = M^{a} {(L T^{- 2})}^{b} T^{c}$

Thus, E = k mg² T²

$\frac{Δ E}{E} = 2 . \frac{Δ g}{g} + 2 . \frac{Δ T}{T}$

Percentage error in E = 2 * 4 + 2 * 3 = 14%

0 0

New answer posted

6 months ago

Physics Oscillations Class 11th

If the length of the pendulum in pendulum clock increases by 0.1%, then the error in time per day is

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

$\frac{Δ T}{T} = \frac{1}{2} \frac{Δ l}{l}$

$\Rightarrow Δ T = \frac{1}{2} * \frac{0.1}{100} * 24 * 60 * 60 = 43.2 s$

0 0

New answer posted

6 months ago

Physics Oscillations Oscillations

The displacement simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is:

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

$x = A s i n ω t$

Angle travelled by while moving from A to B

$θ = 30 ° = \frac{π °}{6}$

$θ = ω t$

$\frac{π}{6} = ω * 3 [t = 3 s e c]$

$ω = \frac{π}{18}$

$\Rightarrow T = \frac{2 π}{ω} = \frac{2 π * 18}{π} = 36 s e c$

T = 36 sec

0 0

New answer posted

6 months ago

Physics Oscillations Oscillations

In figure (A), mass '2 m' is fixed on mass 'm' which is attached to two spring of spring constant k. In figure (B), mass 'm' is attached to two springs of spring constant 'k' and '2k'. If mass 'm' in (A) and in (B) are displaced by distance 'x' horizontally and then released, then time period T₁ and T₂ corresponding to (A) and (B) respectively follow the relation.

0 Follower 5 Views

Vishal Baghel

Contributor-Level 10

$T_{1} = 2 π \sqrt[]{\frac{3 m}{2 k}}$

$T_{2} = 2 π \sqrt[]{\frac{m}{3 k}}$

$\frac{T_{1}}{T_{2}} = \frac{2 π \sqrt[]{\frac{3 m}{2 k}}}{2 π \sqrt[]{\frac{m}{3 k}}} = \frac{3}{\sqrt[]{2}}$

0 0

New answer posted

6 months ago

Physics Oscillations Class 11th

The length of a seconds pendulum at a height h = 2R from earth surface will be:

(Given R = Radius of earth and acceleration due to gravity at the surface of earth, g = $π^{2} m s^{- 2}$ )

0 Follower 5 Views

Payal Gupta

Contributor-Level 10

As we know that

$g_{P} = g {(\frac{R}{R + h})}^{2} = g {(\frac{R}{R + 2 R})}^{2} = \frac{g}{9}, s o$

$T = 2 π \sqrt[]{\frac{l}{g_{P}}} \Rightarrow l = \frac{g_{p} T^{2}}{4 π^{2}} = \frac{1}{9} m$

0 0

New answer posted

6 months ago

Physics Oscillations Class 11th

The metallic bob of simple pendulum has the relative density. 5 The time period of this pendulum is 10 s. If the metallic bob is immersed in water, then the new time period becomes $5 \sqrt[]{x} s .$ The value of x will be_______.

0 Follower 3 Views

alok kumar singh

Contributor-Level 10

g_eff = g – $(\frac{ρ_{w}}{ρ_{b}}) g$

$T = 2 π \sqrt[]{\frac{l}{g}}$

$T' = 2 π \sqrt[]{\frac{l}{g_{e f f}}}$

$\Rightarrow T' = \sqrt[]{\frac{5}{4}} T$

= $\sqrt[]{\frac{5}{4}} * 10$

= $5 \sqrt[]{5} s e c$

So, x = 5

0 0

New answer posted

6 months ago

Physics Oscillations Class 11th

A mass 0.9kg, attached to a horizontal spring, executes SMH with an amplitude A₁. When this mass passes through its mean position, then a smaller mass of 124 g is placed over it both masses move together with amplitude A₂. If the ratio $\frac{A_{1}}{A_{2}} i s \frac{α}{α - 1},$ then the value of a will be______.

0 Follower 4 Views

Payal Gupta

Contributor-Level 10

$m_{1} = 900 g m, w_{1} = \sqrt[]{\frac{k}{. 9}}$

$m_{2} = 1024 g m, ω_{2} = \sqrt[]{\frac{k}{1.024}}$

$m_{1} v_{1} = m_{2} V_{2}$

$\Rightarrow m_{1} ω_{1} A_{1} = m_{2} ω_{2} A_{2}$

$\Rightarrow \frac{A_{1}}{A_{2}} = \sqrt[]{\frac{1024}{900}} = \frac{32}{30} = \frac{16}{15} = \frac{16}{16 - 1}$

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

66k Colleges
1.2k Exams
686k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Physics Oscillations

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience