Physics Oscillations
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2 months agoContributor-Level 10
Given the decay equation A = A? e^ (-bt/m):
-bt/m = ln (A/A? )
Solving for b:
b = (-m/t? ) * ln (A/A? ) = (-1 / (2 * 60) * ln (6/12) = 5.775 * 10? ³ kg/s
New question posted
2 months agoNew answer posted
2 months agoContributor-Level 10
f = V (n)/ (4 (1 - 17/100) (as closed from end)
f = (n - 2) (v)/ (4 (1 - 24.5/100)
nV (100)/4 (83) = (n - 2) (v) (100)/ (4) (75.5)
75.5n = 83 (n - 2)
75.5n = 83 (M - 2)
7.5n = 166
n = 22 (approx)
f = (330) (22) (100)/ (4 (83) = 2200 Hz
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