Tags Physics Oscillations

Physics Oscillations

Get insights from 117 questions on Physics Oscillations, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics Oscillations

Follow Ask Question

117

Questions

Discussions

Active Users

Followers

New answer posted

2 weeks ago

Physics Oscillations Class 11th

The motion of a simple pendulum executing S.H.M. is represented by the following equation. $y = A s i n (π t + ?),$ where time is measured in second.

The length of pendulum is

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

According to question, we can write

$ω = π = \sqrt[]{\frac{g}{l}} \Rightarrow l = \frac{g}{π^{2}} = \frac{9.8}{{(3.14)}^{2}} = 0.99395 = 99.4 c m$

0 0

New answer posted

2 weeks ago

Physics Oscillations Class 11th

Time period of a simple pendulum in a stationary lift is 'T'. If the lift accelerated with $\frac{g}{6}$ vertically upwards then the time period will be:

(Where g = acceleration due to gravity)

0 Follower 2 Views

Raj Pandey

Contributor-Level 9

$g_{e f f} = g + a$

$= g + \frac{g}{6}$

$= \frac{7 g}{6}$

$T' = 2 π \sqrt[]{\frac{l}{g_{e f f}}}$

$T' = \sqrt[]{\frac{6}{7}} T$

0 0

New answer posted

2 weeks ago

Physics Oscillations Class 11th

In an experiment to determine the velocity of sound in air at room temperature using a resonance tube, the first resonance is observed when the air column has a length of 20.0 cm for a tuning form of frequency 400 Hz is used. The velocity of the sound at room temperature is 336 ms^-¹. The third resonance is observed when the air column has a length of ____________cm.

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

According to Concept of resonance tube, we can write

$\frac{λ}{4} + e = l_{1} a n d \frac{3 λ}{4} + e = l_{2} \Rightarrow \frac{λ}{2} = l_{2} - l_{1} \Rightarrow \frac{V}{2 ν} = l_{2} - l_{1}$

$\Rightarrow l_{2} = \frac{v}{2 ν} + l_{1} = \frac{336}{400} + 0.20 = 0.84 + 0.20 = 1.04 m = 104 c m$

0 0

New answer posted

2 weeks ago

Physics Oscillations Class 11th

The motion of a simple pendulum executing S.H.M. is represented by the following equation. $y = A s i n (π t + ϕ),$ where time is measured in second.

The length of pendulum is

0 Follower 3 Views

alok kumar singh

Contributor-Level 10

According to question, we can write

$ω = π = \sqrt[]{\frac{g}{l}} \Rightarrow l = \frac{g}{π^{2}} = \frac{9.8}{{(3.14)}^{2}} = 0.99395 = 99.4 c m$

0 0

New answer posted

2 weeks ago

Physics Oscillations Class 11th

For an SHM oscillator, the amplitude is 5 cm and its time period is 4 seconds. The minimum time taken by the particle to pass between points which are at distances 4 cm and 3 cm from the centre of oscillation on the same side of it will be

0 Follower 5 Views

alok kumar singh

Contributor-Level 10

$y = A \sin ? \frac{2 π t}{T}$

$t_{2} - t_{1} = \frac{T}{2 π} [\sin^{- 1} ? \frac{x_{1}}{A} - \sin^{- 1} ? \frac{x_{2}}{A}]$

0 0

New answer posted

2 weeks ago

Physics Oscillations Class 11th

If we want that a simple pendulum oscillates with same time period in summer as it did in winter, what changes to the simple pendulum should we do during summer?

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$T = 2 π \sqrt[]{\frac{l}{g}}$

In summer, length will increase due to expansion, hence for same time period we have to decrease $l$ in summer.

0 0

New question posted

3 weeks ago

Physics Oscillations Class 11th

A rod is clamped at both of its ends and stationary longitudinal waves are produced in it. In first experiment, the rod has a total of 4 nodes with amplitude of each anti-node to be 1mm. In other experiment, the rod has a total of 6 nodes with amplitude of each anti node to be 2mm. The energy of vibrations in the rod in two case is E₁ and E₂ respectively. Write value of

0 Follower 2 Views

New answer posted

3 weeks ago

Physics Oscillations Class 11th

Two particles are executing SHM which are described by the equations x₁ = asin(ωt + π/6) and x₂ = asin(ωt + π/4). Find the minimum time interval between the particles to cross their mean position.

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

at t = t? , x? = 0 ⇒ 0 = asin (ωt? + π/6)
⇒ ωt? + π/6 = π
at t = t? , x? = 0 ⇒ 0 = asin (ωt? + π/4)
⇒ ωt? + π/4 = π
From (i) and (ii)
ω (t? - t? ) = π/4 - π/6 ⇒ t? - t? = π/ (12ω)

0 0

New answer posted

3 weeks ago

Physics Oscillations Class 11th

A string of mass per unit length $μ$ is clamped at both ends such that one end of the string is at x = 0 and the other end at x = L. When string vibrates in fundamental mode, amplitude of the midpoint of string is a and tension is string is F. Find the total oscillation energy (in J) stored in the string.

(Use L = 1m, F = 10 N, a = $\frac{1}{π} m)$