Physics System of Particles and Rotational Motion

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3 weeks ago

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alok kumar singh

Contributor-Level 10

I = ( 2 5 M R 2 + M R 2 ) * 2

= 1 4 5 * 2 * 9 1 6

= 6 3 2 0          

= 3.15 kg m2

New answer posted

3 weeks ago

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alok kumar singh

Contributor-Level 10

Angular impulse = Change in angular momentum

[J] = [mvr]

[J] = [M1L2T–1]

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3 weeks ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

3 weeks ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

COM for half ring =2R/π

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alok kumar singh

Contributor-Level 10

Distance of CM from 5 kg = 10*2/15 = 4/3m

 

New answer posted

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

3 weeks ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

3 weeks ago

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alok kumar singh

Contributor-Level 10

In rotational motion, angular velocity of every particle on rigid body will be same. But linear velocity is given as v = r ? .

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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4 weeks ago

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alok kumar singh

Contributor-Level 10

Angular momentum imparted to sprinkler per

s e c o n d = v r d m d t = 0.6 60 * 0.5 * 1 = 0.005 N . m

? l d ω d t = 0.005

? d ω d t = 0.005 500 * 10 - 7

= 100 r a d s 2

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