Physics System of Particles and Rotational Motion

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New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

By conservation of Angular momentum

Li = Lf 

M R 2 ω = ( m R 2 + 2 m R 2 ) ω '

2 M M + 2 m = ω '

ω ' = 2 M M + 2 m

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

According to question, we can write

l = 2 π r r = l 2 π  

I 1 = m l 2 3 , a n d I 2 = m r 2 2 = m l 2 8 π 2

I 1 I 2 = m l 2 3 * 8 π 2 m l 2 = 8 π 2 3

 

New answer posted

a month ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Angular retardation,

 

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

I = m 4 * a 2 3 * 2 + m 4 * ( a 2 1 2 + ( a 2 ) 2 + a 2 ) * 2

= m a 2 6 + 2 3 m a 2 = m a 2 + 4 m a 2 6 = 5 m a 2 6

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

L = r * m v

= ( 3 i ^ j ^ ) * ( 3 j ^ + k ^ )

= 9 k ^ + 3 ( j ^ ) i ^

= i ^ 3 j ^ + 9 k ^

| L | = 1 + 9 + 8 1 = 9 1

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

I A B = m ( 0 ) 2 + 2 m a 2 2 + 3 m a 2 2

I A B = m a 2 2 + 3 m a 2 4 = 5 m a 2 4 I A B = 25 m a 2 20 = N 20 m a 2 N = 25

 

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

τ ? = d L ? d t = A ? * L ? d L ? d t L ?

Statement (1) is correct

 

The component of L ?  in the direction of A ?  is always perpendicular to  , so it does not change.

 Statement (2) is correct

The magnitude of L ?  does not change with time as τ ? L ?  .

 Statement (3) is correct

The direction of  L ? changes with time.

Statement (4) is incorrect.

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

L = Iω
I = (mL²/3) + (mL²/3) + [m (√2L)²/12] + m (L/√2)² = mL² [2/3 + 1/6 + 1/2] = (4mL²/3); L = (4/3)mL²ω

New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Using parallel axis theorem for the side BC, the moment of inertia of the triangle about an axis passing through A and perpendicular to the plane of the triangle,
I? = 2 [ (1/3)ma²] + [ (1/12)ma² + m (√3a/2)²] = (3/2)ma²
If the angular velocity of the triangle at any instant is ω, the velocity of the vertex B at that instant is aω
Therefore, the velocity of B is maximum at the instant the angular velocity is maximum, i.e. when the side BC becomes horizontal
Let the angular velocity at this instant be ω?
Then, by conservation of energy
Gain in kinetic energy = Loss in potential energy
(1/2)I? ω²? = 3mg (Loss in height of CM of tr

...more

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

l 1 = 1 2 m r 2

l 2 = 1 2 m r 2 l 3 = 1 2 m r 2 l 4 = 2 5 m r 2

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