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New answer posted
7 months agoContributor-Level 10
Δl = lαΔT ⇒ Δl/l = αΔT = 0.02%
Δρ = -ργΔT
|Δρ/ρ| = γΔT = 3αΔT = 3 (0.02%) = 0.06%
New answer posted
7 months agoContributor-Level 10
2θ = 60° ⇒ θ = 30°
h = 2Tcosθ / (ρsg) = 2 (0.05)cos30° / (667) (0.15 * 10? ³) (10) = (√3 * 100)/ (667 * 3) ≈ 173.2/2000 m = 8.66 cm
New answer posted
7 months agoContributor-Level 10
The excess pressure inside a soap bubble is given by ΔP = 4T/R, where T is the surface tension and R is the radius.
The pressures are given as P? = 1.01 atm and P? = 1.02 atm. Let the atmospheric pressure be P? = 1 atm.
ΔP? = P? - P? = 1.01 - 1 = 0.01 atm = 4T/R?
ΔP? = P? - P? = 1.02 - 1 = 0.02 atm = 4T/R?
Dividing the two equations: (ΔP? /ΔP? ) = (R? /R? )
0.01 / 0.02 = R? /R? ⇒ R? /R? = 2
The ratio of their volumes is V? /V? = ( (4/3)πR? ³ ) / ( (4/3)πR? ³ ) = (R? /R? )³ = 2³ = 8.
The ratio is 8:1.
New answer posted
7 months agoContributor-Level 10
The law of radioactive decay is N = N? e? λt, where N is the amount remaining at time t.
Given that at time t, N/N? = 9/16.
So, 9/16 = e? λt
At time t/2, the fraction remaining will be N'/N?
N' = N? e? λ ( t/2 ) = N? (e? λt)¹/²
Substituting the value of e? λt:
N' = N? (9/16)¹/² = N? (3/4)
The fraction remaining is N'/N? = 3/4.
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