Physics

Get insights from 5.6k questions on Physics, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics

Follow Ask Question
5.6k

Questions

0

Discussions

28

Active Users

0

Followers

New answer posted

4 months ago

0 Follower 36 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

4 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

a = ω²l = (2π/T)²l = (2π/60)²*0.1 = 1.1*10? ³ m/s²

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

λ=h/p, p=√2mk. λ∝1/√m

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

v_max/v_min = (1+e)/ (1-e)
r_max/r_min = (1+e)/ (1-e) = 6

New answer posted

4 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

µ=tanθ ⇒ 3/4=tanθ ⇒ θ=37°
h = R-Rcosθ = 1-1 (4/5)=0.2m

New answer posted

4 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

r = mv/qB?
To not collide, r∴ Vmax = qB? d/m
Note: It should be maximum instead of minimum.

New answer posted

4 months ago

0 Follower 18 Views

V
Vishal Baghel

Contributor-Level 10

τ = RC = 10µS
For 0

New answer posted

4 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

I = m (l/√2)²*2 + m (√2l)² = 3ml²
L=Iω = 3ml²ω

New answer posted

4 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

4 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Net field along AB at O must be zero.
E? cosα = E? sinα
(kQ? /x? ²) (x? /AB) = (kQ? /x? ²) (x? /AB)
Q? /Q? = x? ³/x? ³

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 681k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.