Physics
Get insights from 5.6k questions on Physics, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
a year agoContributor-Level 10
l = 10 * pitch = 10 * (2πmvcosθ/qB)
= 20π * 1.67*10? ²? * 4*10? * (1/2) / (1.6*10? ¹? * 0.3) = 0.44 m
New answer posted
a year agoContributor-Level 10
λ = h/p = h/mv
λp/λe = (m? v? )/ (m? v? ) ⇒ 1.878 * 10? = (9.1*10? ³¹)/ (m? * 5)
m? = 9.1*10? ³¹ / (5 * 1.878 * 10? ) = 0.97 * 10? ²? kg
New answer posted
a year agoContributor-Level 10
Δl = lαΔT ⇒ Δl/l = αΔT = 0.02%
Δρ = -ργΔT
|Δρ/ρ| = γΔT = 3αΔT = 3 (0.02%) = 0.06%
New answer posted
a year agoContributor-Level 10
2θ = 60° ⇒ θ = 30°
h = 2Tcosθ / (ρsg) = 2 (0.05)cos30° / (667) (0.15 * 10? ³) (10) = (√3 * 100)/ (667 * 3) ≈ 173.2/2000 m = 8.66 cm
New answer posted
a year agoContributor-Level 10
The excess pressure inside a soap bubble is given by ΔP = 4T/R, where T is the surface tension and R is the radius.
The pressures are given as P? = 1.01 atm and P? = 1.02 atm. Let the atmospheric pressure be P? = 1 atm.
ΔP? = P? - P? = 1.01 - 1 = 0.01 atm = 4T/R?
ΔP? = P? - P? = 1.02 - 1 = 0.02 atm = 4T/R?
Dividing the two equations: (ΔP? /ΔP? ) = (R? /R? )
0.01 / 0.02 = R? /R? ⇒ R? /R? = 2
The ratio of their volumes is V? /V? = ( (4/3)πR? ³ ) / ( (4/3)πR? ³ ) = (R? /R? )³ = 2³ = 8.
The ratio is 8:1.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 67k Colleges
- 1.2k Exams
- 718k Reviews
- 1850k Answers




