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New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Pitch = (Vcosθ)T = (Vcosθ)2πm/eB
= (4*10? cos60°) (2π (1.67*10? ²? )/ (0.3*10? ¹? *1.69*10¹? )
= 4 cm

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

(f? n? RT? )/2 + (f? n? RT? )/2 = 3/2 RT + 5/2 * 3RT = 15

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

From Given equation
µ = 0.6
A? = µA?
(A? - A? )/2 = A? = 5
(A? + A? )/2 =?
A? - A? = 3
From equation (1)+ (2)
A? = 8
From equation (1)- (2)
A? = 2

New answer posted

7 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

Let AC = l, BC = 2l, AB = 3l
Apply work-Energy theorem
W? + W? = ΔKE
Mg (3l)sinθ - µmgcosθ (l) = 0+0
µmgcosθl = 3mglsinθ


µ=3tanθ = ktanθ
∴ k=3

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Y ∝ F? V? A? Y = (E/A)/L²
ML? ¹T? ² ∝ (M¹L¹T? ²)? (L¹T? ¹)? (L²)?
a=1, a+b+2c=-1, -2a-b=-2
a=1, b=0, c=-1
Y = F¹V? A? ¹

New answer posted

7 months ago

0 Follower 26 Views

V
Vishal Baghel

Contributor-Level 10

Heat loss; ΔH = U? - U? = 1/2 (C? / (C? +C? ) (V? -V? )²
= 1/2 * (5*2.5)/ (5+2.5) (220-0)²µJ
= 5/ (2*3) * 22*22*100*10? J
= 5*11*22/3 * 10? J = 1210/3 * 10? J = 1210/3 * 10? ³ J * 4 * 10? ²
According to questions
x/100 = 4*10? ²
So, x=4
Note: But given answer by JEE Main x=36

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

hc/λ = Φ + eV
hc/3λ = Φ + eV/4
from (1) and (2)
hc/λ (1-1/3) = 3/4 eV
eV = 8/9 hc/λ
eV = 8/9 (hc/λ - Φ)
Φ = hc/9λ
λ? = 9λ ∴k=9

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

T? V? ¹ = T? V? ¹
T? = T? (V? /V? )? ¹ = T? (10)? /? ¹ = T? (10)²/?
ΔV = 5/2 nR; 5/2 * 5 * 3102/5-1
625/6 * 1.5 * 293 = 461440 ≈ 46ks

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

From momentum conservation
mui + 0 = mvj + 3mv'
v' = u/3 I - v/3 j
From kinetic energy conservation 1/2 mu² = 1/2 mv² + 1/2 (3m) (u/3)²+ (v/3)²)
Solving, v = u/√2

New answer posted

7 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

Flux as a function of time Φ = B.A = ABcos (ωt) emf induced,
e = -dΦ/dt = ABωsin (ωt)
Maximum value of emf = ABω = πR²Bω
= 3.14*0.1*0.1*3*10? * (0/0.2) = 15

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