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New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

mω²acosθ = mgsinθ
ω = √ (gtanθ/a)
y = 4cx²

tanθ = dy/dx = 8xC
(tanθ)? , b = 8aC
ω = √ (g*8aC/a) = 2√ (2gC)

 


New answer posted

4 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

ρ? = 98 * 10?
ρ? = 2.65 * 10?
ρc = 1.724 * 10?
ρT = 5.65 * 10?

New answer posted

4 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

ΔP = dsinθ = dθ
dy/D = (10? ³ * 1.270mm)/1m = 1.27µm

New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

M = ∫ ρdV
M = ∫? (k/r) 4πr²dr
M = 4πkR?²/2 = 2πkR?²
F? = GMm/R?² = 2ω?²R

 

New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

FR > mgcosθR
F > mgcosθ
F > mg √ (R²- (R-a)²)/R ⇒ Mg√ (1- (R-a)²/R²)

 

New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Zero error = 0 + 7 * 0.1 = 0.070
Vernier reading = (3.1 + 4 * 0.01) – 0.07 = 3.07

New answer posted

4 months ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

x > d path is straight line
-y = 1/2 at²
x-d = V?t ⇒ t=(x-d)/V?
-y = 1/2 a((x-d)/V?)²
-y/at = (1/2at)(a²t²)
at = V?
(-y/at) = (d/2V?)
(x-d)/V? = d/V?
(-y - 1/2 a t²)/(at) = (x-d - V?t)/V?
y = (-qEd/mV?)(x/V? - d/2V?) ; y = (qEd/mV?²)(d/2 - x)

 

New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

f? = 1/ (2l) √ (T? /µ)
f? = 1/ (2l) √ (T? /µ)
f? /f? = 450/300 = √ (T? /T? )
⇒ T? /T? = 9/4 = 2.25

New answer posted

4 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Based on theory.

New answer posted

4 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Energy Density = 1/2 B²/µ?
B = √ (2 * µ? * Energy density)
B = √ (2 * 4π * 10? * 1.02 * 10? ) = 160 * 10? = 160nT

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