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11 months ago

Physics Nuclei

How does the nuclear force contribute to nuclear stability?

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Jaya Sharma

Contributor-Level 10

Nuclear force is important to maintain the stability of an atomic nucleus for the following reasons:

A nucleus has positively charged sub-particles called protons. Since like charges repel each other, a nucleus, in ideal scenario, should fall apart because protons won't be able to coexist in the nucleus. However, nuclear force is extremely strong at very short range. Due to this reason, protons stay bound within nucleus and therefore, nucleus remains stable.
Nuclear force is responsible for binding energy that holds the nucleons together within a nucleus. Higher binding energy will result in a more stable nucleus.
The nuclear force shows

...more

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11 months ago

Physics Nuclei

How does the nuclear force overcomes repulsion between protons?

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Jaya Sharma

Contributor-Level 10

As we all know that like charges repel each other. This means that there must be a repulsive electromagnetic force between positively charged protons. However, the nuclear force is said to be 100 times stronger than electromagnetic force which makes it strong enough to hold protons together within a nucleus. This nuclear force is much stronger than coulomb force at short ranges.

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11 months ago

Physics Vector Algebra

Three particles P, Q and R are moving along the vectors $\vec{A} = \hat{i} + \hat{j}, \vec{B} = \hat{j} + \hat{k}$ and $\vec{C} = - \hat{i} + \hat{j}$ respectively. They strike on point and start to move in different directions. Now particle P is moving normal to the plane which contains vector $\vec{A} a n d \vec{B} .$ Similarly particle Q is moving normal to the plane which contains vector $\vec{A} a n d \vec{C} .$ The angle between the direction of motion of P and Q $c o s^{- 1} (\frac{1}{\sqrt[]{x}}) .$ Then the value of x is_________.

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Vishal Baghel

Contributor-Level 10

Cross product will represent a vector perpendicular to both the vector.

Dir. Of Motion of P : $= (\hat{i} + \hat{j}) * (\hat{j} * \hat{k})$

= $\hat{k} - \hat{j} + \hat{i}$

Dir. Of Motion of Q = $(\hat{i} + \hat{j}) * (- \hat{i} + \hat{j})$

$= 2 \hat{k}$

$c o s θ = \frac{\vec{a} . \vec{b}}{a b} = \frac{2}{2 \sqrt[]{3}} = \frac{1}{\sqrt[]{3}} \Rightarrow θ = c o s^{- 1} (\frac{1}{\sqrt[]{3}})$

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11 months ago

Physics Class 12th

In a given circuit diagram, a 5 V zener diode along with a series resistance is connected across a 50 V power supply. The minimum value of the resistance required, if the maximum zener current is 90 mA be________ $Ω$ .

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Vishal Baghel

Contributor-Level 10

For 90 mA in zener diode, current in R should be greater than 90 mA.

$\frac{45}{R} = 90 * 1 0^{- 3} \Rightarrow R = \frac{45}{90 * 1 0^{- 3}} = 500 Ω$

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11 months ago

Physics Class 12th

In an electric circuit, a cell of certain emf provides a potential difference of 1.25 V across a load resistance of $5 Ω$ . However, it provides a potential difference of 1V across a load resistance of $2 Ω .$ The emf of the cell is given by $\frac{x}{10} V .$ Then the value of x is_________.

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Vishal Baghel

Contributor-Level 10

$i = \frac{ε}{R + r}$

$v_{R} = \frac{ε R}{R + r}$

$\frac{1.25 = \frac{ε (5)}{5 + r}}{1 = \frac{ε (2)}{2 + r}}$

r = 1

Using above equ : $ε = \frac{3}{2} = \frac{15}{10} V$

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11 months ago

Physics Mechanical Properties of Solids

The area of cross – section of a railway track is 0.01 m². The temperature variation is 10°C, Coefficient of linear expansion of material of track is 10^-⁵ / °C. The energy stored per meter in the track is_________J/m.

(Young's modulus of material of track is 10¹¹ Nm^-²)

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Vishal Baghel

Contributor-Level 10

Energy density (u) = $\frac{1}{2} * σ * ε = \frac{1}{2} * Y ε * ε = \frac{1}{2} ε^{2} Y$ $\frac{}{} \frac{}{} \frac{}{}^{}$

$\Rightarrow e n e r g y s t o r e d / m^{2} = \frac{1}{2} ε^{2} Y A$

Strain $(ε) = \frac{Δ l}{l_{0}} = α Δ T = 1 0^{- 5} * 10 = 1 0^{- 4}$ $\frac{}{_{}}^{}^{}$

$\Rightarrow e n e r g y s t o r e d / m^{2} = \frac{1}{2} * 1 0^{- 8} * 1 0^{11} * 1 0^{- 2} = 5$

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11 months ago

Physics Thermodynamics

In 5 minutes, a body cools from 75°C to 65°C at room temperature of 25°C. The temperature of body at the end of next 5 minutes is__________°C.

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Vishal Baghel

Contributor-Level 10

from newtan's law of cooling :

$\frac{d T}{d t} = - k (T - T_{0})$

Using average value :

$\frac{75 - 65}{5} = - k [\frac{(75 + 65) 2}{2} - 25]$

$\frac{(65 - T)}{5} = - k [\frac{(65 + T)}{2} - 25]$

$\Rightarrow \frac{10}{65 - T} = \frac{45}{\frac{65 + T}{2} - 25}$

$\Rightarrow T = 57 ° C$

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11 months ago

Physics Units and Measurement

Three students S₁, S₂ and S₂ perform an experiment for determining the acceleration due to gravity (g) using a simple pendulum. They use different lengths of pendulum and record time for different number of oscillations. The observations are as shown in the table.

Student No.	Length of Pendulum (cm)	No. of oscillations (n)	Total for n oscillations	Time period (s)
1	64.0	8	128.0	16.0
2	64.0	4	64.0	16.0
3	20.0	4	36.0	9.0

Least count of length = 0.1 cm

least count for time = 0.1 s)

If E₁, E₂ and E₃ are the percentage errors 'g' for students 1, 2 and 3 respectively, then the minimum percentage error is obtained by student no.___________.

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Vishal Baghel

Contributor-Level 10

$T = 2 π \sqrt[]{\frac{l}{g}}$

$g = 4 π^{2} \frac{l}{T^{2}}$

$\Rightarrow \frac{Δ g}{g} = \frac{Δ l}{l} + \frac{2 Δ T}{T}$

Student 1 will get least error because it has more number of oscillation

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11 months ago

Physics System of Particles and Rotational Motion

The centre of a wheel rolling on a plane surface moves with a speed $υ_{0} .$ A particle on the rim of the wheel at the same level as the centre will be moving at a speed $\sqrt[]{x} υ_{0} .$ Then the value of x is__________.

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Vishal Baghel

Contributor-Level 10

$V_{P} = \sqrt[]{V_{0}^{2} + V_{0}^{2}} = \sqrt[]{2} V_{0}$

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New answer posted

11 months ago

Physics Class 12th

A ray of light passing through a prism $(μ = \sqrt[]{3})$ surface minimum deviation. It is found that the angle of incidence is double the angle of refraction within the prism. Then, the angle of prism is________(in degrees).

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Vishal Baghel

Contributor-Level 10

At minimum deviation :

i = i'

r = r'

$r + r' = A \Rightarrow r = \frac{A}{2}$

Snell's law :

1 sin I = $\sqrt[]{3} s i n r = \sqrt[]{3} s i n \frac{i}{2}$ $\frac{}{}$

$\Rightarrow 2 c o s \frac{i}{2} = \sqrt[]{3}$

$\Rightarrow i = 60 °$

$\begin{array}{l} i = 2 r \Rightarrow r = 30 ° \\ \Rightarrow A = 60 ° \end{array}$

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