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New answer posted

8 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Using conservation of energy:

m g h = 1 2 l c m ω 2 + 1 2 m v 2 = 1 2 l c m V 2 r 2 + 1 2 m v 2

v 2 = m g h 1 2 l c m r 2 + m v 2

So, sphere has the greatest velocity of COM and ring has least.

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Total energy of monoatomic gas at equilibrium

= 3 2 K B T

New answer posted

8 months ago

0 Follower 22 Views

V
Vishal Baghel

Contributor-Level 10

x (t) = A sin ω  t + B cos ω t

x ( t ) = A 2 + B 2 s i n ( ω t + δ ) = A 2 + B 2 c o s ( ω t ( π 2 δ ) )

At t = 0:

x ( 0 ) = A 2 + B 2 s i n ( δ )

v ( 0 ) = ω A 2 + B 2 c o s ( δ )

( x ( 0 ) ) 2 + ( v ( 0 ) ω ) 2 = A 2 + B 2

t a n ? = t a n ( π 2 δ ) = c o t δ = v ( 0 ) x ( 0 ) ω

? = t a n 1 ( v ( 0 ) x ( 0 ) ω )

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

True dip is less than the apparent dip.

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

d = 150 km

d = 2 h R

h = d 2 2 R = ( 1 5 0 * 1 0 3 ) 2 2 * 6 . 5 * 1 0 6 = 1 7 3 1 m .

Population covered

π r 2 * σ = 3 . 1 4 * 1 5 0 2 * 2 0 0 0 = 1 4 1 3 * 1 0 5

New answer posted

8 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

for bullet

l = Δ p = m v 0

= 4 1 0 0 0 * 5 0 = 2 0 1 0 0 = 0 . 2 k g m / s

Using conservation of momentum :

Pi = Pt

4 1 0 0 0 * 5 0 = 4 * v

v = 0.05 m/s

New answer posted

8 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

I : at high temperature, ferromagnet becomes paramagnet.

II : at high temperature, domains of ferromagnet will break

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

T T ' = 2 π l g 2 π l 1 6 g

T T ' = 1 ( 1 4 ) = 4

T ' = T 4

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

W = mgh

      

= 8 0 * 9 . 8 * ( 8 0 1 0 0 )

= 6 2 7 . 2 J

w f + w g = 0 w f = 6 2 7 . 2 J  

New answer posted

8 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

E = h c λ = 1 2 4 2 e V n m 6 2 1 n m = 2 e V

minimum 2eV is required to emit.

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