Physics

Get insights from 5.6k questions on Physics, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics

Follow Ask Question
5.6k

Questions

0

Discussions

19

Active Users

0

Followers

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  X = ( A + B ¯ ) + ( A ¯ + B ) ¯

( A + B ¯ ¯ ) ( A ¯ + B ¯ )

( A ¯ B ¯ ) ( A ¯ B ¯ )

( A ¯ B ) ( A B ¯ ) = A ¯ B A B ¯ = 0  

             

             

           

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  1 f = ( μ 1 ) ( 2 R )                    f = 20 cm

1 v 1 u = 1 f

1 v + 1 1 0 = 1 2 0

             

             

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Since f 2 < f 0  

->current = 0

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

= IV cosf

= 2 0 2 * 2 2 *  cos 60°

= 10 W

 

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go though the solution 

v = γ R T M = 3 3 0 m / s

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

p = i2R

P' = 0.64 i2R

New answer posted

a month ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

I = ( 2 5 M R 2 + M R 2 ) * 2

= 1 4 5 * 2 * 9 1 6

= 6 3 2 0          

= 3.15 kg m2

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

By Brewsters law

m = tani

m =   3

1 * 3 2 = 3 * s i n r

s i n r = 1 2    

r = 30°

New answer posted

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

[A] = L2

B = x 2 t E L 2 T M L 2 T 2 = 1 M T 1            

[B] = M–1T

[AB] = [M–1L2T]

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

P = F v

= 18t4 – 18t2

->P (t = 2) =18 [16 − 4] = 216 W

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.