Physics

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New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

In air F = 1 4 π 0 q 1 q 2 r 2  

In medium F ' = 1 4 π ( k 0 ) q 1 q 2 r 2  

F ' = F 0 K

New answer posted

3 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

a = ( m 1 m 2 ) g ( m 1 + m 2 ) = g 8

8m1 – 8m2 = m1 + m2

7m1 = 9m2

m 1 m 2 = 9 7          

New answer posted

3 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

U = nCvT

-> U = n 1 C v 1 T + n 2 C v 2 T  

-> 8 * 5 R 2 * T + 4 * 5 R 2 * T

= 30RT

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

d ? d t = 1 0 t 3            

at t = 2, V = 17

i = V R = 1 7 8 A              

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  X = ( A + B ¯ ) + ( A ¯ + B ) ¯

( A + B ¯ ¯ ) ( A ¯ + B ¯ )

( A ¯ B ¯ ) ( A ¯ B ¯ )

( A ¯ B ) ( A B ¯ ) = A ¯ B A B ¯ = 0  

             

             

           

New answer posted

3 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

  1 f = ( μ 1 ) ( 2 R )                    f = 20 cm

1 v 1 u = 1 f

1 v + 1 1 0 = 1 2 0

             

             

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Since f 2 < f 0  

->current = 0

New answer posted

3 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

= IV cosf

= 2 0 2 * 2 2 *  cos 60°

= 10 W

 

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go though the solution 

v = γ R T M = 3 3 0 m / s

New answer posted

3 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

p = i2R

P' = 0.64 i2R

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