Tags Physics

Physics

Get insights from 5.6k questions on Physics, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics

Follow Ask Question

5.6k

Questions

Discussions

Active Users

Followers

New answer posted

9 months ago

Physics Oscillations

In a vernier calipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be__________* 10^-2mm.

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

Let 'x' he the value of one division of main scale

$x = \frac{1}{20} c m = 0.05 c m$

Let y be value of one division on venire scale given

10 y = 9 x

$y = \frac{9 x}{10}$

Least count = $x - \frac{9 x}{10} = \frac{x}{10} = \frac{0.05}{10}$

= 0.005 cm

= 5 * 10^-2 mm

0 0

New answer posted

9 months ago

Physics Ray Optics and Optical Instruments

A light ray is incident, at an incident angle q₁, on the system of two plane mirrors M₁ and M₂ having an inclination angle 75° between them (as shown in figure). After reflecting from mirror M₁ it gets reflected back by the mirror M₂ with an angle of reflection 30°. The total deviation of the ray will be ___________ degree.

0 Follower 13 Views

Payal Gupta

Contributor-Level 10

$δ_{t o t a l} = 360 ° - 2 θ$

= 360 – 2 * 75° = 210°

Total deviation = $δ = 150 °$

0 0

New answer posted

9 months ago

Physics physics ncert exemplar solutions class 12th chapter two

The stopping potential for photoelectrons emitted from a surface illuminated by light of wavelength 6630 $\overset{o}{A}$ is 0.42 V. If the threshold frequency is x * 10¹³ /s, where x is ________(nearest integer).

(Given, speed light = 3 * 10⁸ m/s, Planck's constant = 6.63 * 10^-34 Js)

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$e V_{0} + h υ_{0} = \frac{h C}{λ}$

$\Rightarrow 1.6 * 1 0^{- 19} * 0.42 + 6.63 * 1 0^{- 34} υ_{0} = \frac{6.63 * 1 0^{- 34} * 3 * 1 0^{8}}{66 3^{0} * 1 0^{- 10}}$

$\Rightarrow 6.63 * 1 0^{- 34} υ_{0} = 1 0^{- 19} (3 - 1.6 * 0.42)$

$6.63 * 1 0^{- 34} υ_{0} = 2.328 * 1 0^{- 19}$

$υ_{0} = 35.11 * 1 0^{13} = 35$

0 0

New answer posted

9 months ago

Physics physics ncert exemplar solutions class 12th chapter two

A travelling microscope is used to determine the refractive index of a glass slab. If 40 divisions are there in 1cm on main scale and 50 Vernier scale divisions are equal to 49 main scale division, then least count of the travelling microscope is __________* 10^-6 m.

0 Follower 4 Views

Vishal Baghel

Contributor-Level 10

Let 'x' be the value of one division on main scale

$x = \frac{1}{40} c m$

Let 'y' be the value of one division on vernier

Now given

50y = 49 x

$y = \frac{49 x}{50}$

$\begin{array}{l} = 5 * 1 0^{- 4} c m \\ = 5 * 1 0^{- 6} m \\ 5 \end{array}$

0 0

New answer posted

9 months ago

Physics Electric Charges and Fields

A $10 Ω$ 20 mH coil carrying constant current is connected to a battery of 20 V through a switch. Now after switch is opened current becomes zero in 100 $μ s .$ The average e.m.f. induced in the coil is__________V.

0 Follower 4 Views

Payal Gupta

Contributor-Level 10

Decay of current in Inductor is given by,

$i = i_{0} e^{- t / τ} [W h e r e τ = \frac{L}{R}; i_{0} = \frac{v}{R} = \frac{20}{10} = 2]$

At t = 100 $μ s$

i = 0

i.e. i = i0 $e^{- 100 / τ} = 0$ -(1)

e.m.f induced

$e = \frac{- L d i}{d t} = - L \frac{d}{d t} [i_{0} e^{- t / τ}]$

= $= - L i_{0} \frac{- 1}{2} e^{- t / τ}$

$e = \frac{L i_{0}}{τ} e^{- t / τ}$

$e_{a v g} = \frac{\int_{0}^{200 μ s} e d t}{\int_{0}^{200 μ s} d t} = \frac{\int_{0}^{200 μ s} \frac{L i_{0}}{τ} e^{- t / τ} d t}{\int_{0}^{200 μ s} d t}$

$= \frac{L i_{0}}{200 * 1 0^{- 6} s e c} = \frac{20 * 1 0^{- 3} * 2}{200 * 1 0^{- 6}} = 400$

0 0

New answer posted

9 months ago

Physics physics ncert exemplar solutions class 12th chapter two

A small bulb is placed at the bottom of a tank containing water to a depth of $\sqrt[]{7} m .$ The refractive index of water is $\frac{4}{3} .$ The area of the surface of water through which light from the bulb can emerge out is xπm². The value of x is_________.

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

by snell's law

$\frac{4}{3} s i n θ_{C} = μ_{1} s i n 90 °$

$s i n θ_{C} = \frac{3}{4} = \frac{r}{\sqrt[]{r^{2} + {(\sqrt[]{7})}^{2}}}$

$\frac{3}{4} = \frac{r}{\sqrt[]{r^{2} + 7}}$

Squaring both side

$\frac{9}{16} = \frac{r^{2}}{r^{2} + 7}$

$A = r^{2} = π * 9 = 9 π$

0 0

New answer posted

9 months ago

Physics physics ncert exemplar solutions class 12th chapter two

Two 10cm log, straight wires, each carrying a current of 5A are kept parallel to each other. If each wire experienced a force of 10^-5N, then separation between the wires is__________cm.

0 Follower 4 Views

Vishal Baghel

Contributor-Level 10

$F = \frac{μ_{0} * 2}{4 π} \frac{i_{1} i_{2}}{d} l$

$1 0^{- 5} = \frac{1 0^{- 7} * 2 * 5 * 5}{d} = \frac{10}{100}$

$d = 5 * 1 0^{- 2} m$

d = 5 cm

0 0

New answer posted

9 months ago

Physics Nuclei

The elongation of a wire on the surface of the earth is 10^-⁴m. The same wire of same dimensions is elongated by 6 * 10^-⁵ m on another planet. The acceleration due to gravity on the planet will be__________ms^-². (Take acceleration due to gravity on the surface of earth = 10 ms^-²)

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

$Δ L$ (change in length) $= \frac{F l}{A E} = \frac{m g l}{A E}$

$Δ l \propto g$

$\frac{Δ l_{1}}{g_{1}} = \frac{Δ l_{2}}{g_{2}} \Rightarrow \frac{1 0^{- 4}}{10} = \frac{6 * 1 0^{- 5}}{g_{1}}$

$g_{1} = \frac{6 * 1 0^{- 4}}{1 0^{- 4}} =$ 6 m/sec²

0 0

New answer posted

9 months ago

Physics physics ncert exemplar solutions class 12th chapter two

A set of 20 tuning forks is arranged in series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is ___________Hz.

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

A/c to question

f + 76 = 2f

f = 76

last frequency

= f + 76 = 2 * 76

= 152 H₂

0 0

New answer posted

9 months ago

Physics Laws of Motion

A ball of mass 0.5 kg is dropped from the height of 10m. The height, at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity, is __________m.

[Use g = 10m/s²]

0 Follower 4 Views

Payal Gupta

Contributor-Level 10

Let 'h' be the height at which velocity becomes equal to magnitude of Acceleration

v = g = 10

v = u + at

10 = 0 + 10t

t = 1 sec

$h = u t + \frac{1}{2} a t^{2}$

$= 0 * 1 + \frac{1}{2} * 10 * 1 * 1$

= 5m

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

66k Colleges
1.2k Exams
688k Reviews
1850k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Physics

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience