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New question posted

9 months ago

0 Follower 2 Views

New answer posted

9 months ago

0 Follower 12 Views

P
Payal Gupta

Contributor-Level 10

After switch 'S' is closed

Q1+Q2=C1V - (1)

Using KVL

Q1C1Q2C2=0

Q1=Q2C1C2 - (2)

from (1) & (2)

Q2 [C1+C2C2]=C1VQ2= (C1C2C1+C2)V

New answer posted

9 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 g'=gω2Rsinθ

g' (atθ=0pole)=g

g' (atθ=90°, equator)=gω2R

g decreases as we move bole to equator

So, A is false statement

But 'R' statement is true

New answer posted

9 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

KE=ΔU

ΔU=12mv2

nCvΔT=mv22

mMRy1ΔT=mv22

ΔT=0.42Mv2R

ΔT=Mv25R

New answer posted

9 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

K.ER (Rotational) = 12ICMω2=12*25MR2ω2=MR2ω25 - (1)

K.ETotal=K.ER+K.ET

=MR2ω25+12MVcm2

=7MR2ω210 - (2)

k.ERK.ETotal=15*107=27

New answer posted

9 months ago

0 Follower 30 Views

V
Vishal Baghel

Contributor-Level 10

Work done represents are under

F vs x diagram

w3 > w2 > w1 > w4

New answer posted

9 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

 T.a=0

T2a1+T4a2+T8a3+T8a4=0

4a1+2a2+a3+a4=0

New answer posted

9 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

geff=g+a

=g+g6

=7g6

T'=2πlgeff

T'=67T

New answer posted

9 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 e=Mdidt

M=edi/dt=ML2T2A2

 

New answer posted

9 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Steam point (T1) = 100°C = 273 + 100 = 373 K

Ice point (T2) = 0°C = 273 K

η= (1T2T1)*100= (1273373)*100=26.81%

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