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11 months agoContributor-Level 10
14.4 The correct statement is (c).
The diffusion of charge carriers across a junction takes place from the regions of higher concentration to the region of lower concentration. In this case, the p-region has greater concentration of holes than the n-region. Hence, in an unbiased p-n junction, holes diffuse from the p-region to the n-region.
New answer posted
11 months agoContributor-Level 10
14.2 The correct statement is (d).
In a p-type semiconductor, the holes are the majority carriers, while the electrons are the minority carriers. A p-type semiconductor is obtained when trivalent atoms, such as aluminium, are doped in silicon atoms.
New answer posted
11 months agoContributor-Level 10
14.1 The correct statement is (c ).
In an n-type silicon, the electrons are the majority carrier, while the holes are the minority carriers. An n-type semiconductor is obtained when pentavalent atoms, such as phosphorous, are doped in silicon atoms.
New answer posted
11 months agoContributor-Level 10
6.30 The decay process of free neutron at rest is given as:
n
From Einstein's mass-energy relation, we have the energy of electron as? where,
? m = Mass defect = Mass of neutron – ( Mass of proton + mass of electron)
c = speed of light
? m and c are constant. Hence, the given two-body decay is unable to explain the continuous energy distribution in the -decay of a neutron or a nucleus. The presence of neutrino von the LHS of the decay correctly explain the continuous energy distribution.
New answer posted
11 months agoContributor-Level 10
6.29 The potential energy of two masses in a system is inversely proportional to the distance between them. The potential energy of the system of two balls will decrease as they get closer to each other. When the balls touch each other, the potential energy becomes zero, I.e. at r = 2R. The potential energy curve in (i), (ii), (iii), (iv) and (vi) do not satisfy these conditions. So there is no elastic collision.
New answer posted
11 months agoContributor-Level 10
6.28 Mass, m = 200 kg
Speed, v = 36 km/h = 10 m/s
Mass of the boy, M = 20 kg
Initial momentum = (M + m)v = (20 + 200) x 10 kg-m/s = 2200 kg-m/s
If v' is the final velocity of the trolley, then
The final momentum = (M+m) x v' – M x 4= 220v'-80
According to the law of conservation of energy,
Initial momentum = final momentum
2200 = 220v'-80
V' = 10.36 m/s
Time required by the boy to travel 10m = 10/4 = 2.5 s
Distance travel by trolley in 2.5 s = 10.36 x 2.5 m = 25.9 m
New answer posted
11 months agoContributor-Level 10
6.27 Mass of the bolt, m = 0.3 kg, Height of the elevator, h = 3 m
Since the bolt did not rebound, the entire potential energy got converted into heat.
The potential energy of the bolt = mgh = 0.3 x 9.8 x 3 J = 8.82 J
The heat produced will remain same even if the lift is stationary, since g = constant
New answer posted
11 months agoContributor-Level 10
6.26 Mass of the block = 1 kg
Spring constant = 100 N/m
Displacement of the block, x = 10 cm = 0.1 m
At equilibrium, normal reaction, R =
Frictional force, F = =
Net force acting on the block down on the incline = - F
= -
=mg ( )
At equilibrium,
Work done = Potential energy of the stretched string
mg ( ) = (1/2)kx2
1 x 10 x ( ) = (1/2) x 100 x 0.1
10 x (0.602 – = 0.5 x 100 x 0.1
New answer posted
11 months agoContributor-Level 10
6.25 From the law of conservation of energy,
the potential energy at the top = Kinetic energy at the bottom
mgh = (1/2)m ….(1)
and
mgh = (1/2)m ….(2)
= , Both the stones will reach with the same speed
For stone 1, the force acting on the stone 1 is given by , = m = mg
= g
For stone 2, = g
As , >
From v = u + at, we get t = v/a
Therefore < Stone 2 will reach faster than stone 1
From the law of conservation of energy
mgh = (1/2) mv2
v = = 14 m/s ( Given h = 10 m)
The time taken by two stones given as
&
New answer posted
11 months agoContributor-Level 10
6.24 Mass of the bullet, = 0.012 kg
Initial speed of the bullet, u = 70 m/s
Mass of the wooden block , = 0.4 kg
Initial speed of the wooden block = 0
Let's assume, final speed of the bullet = v
Applying the law of conservation of momentum
Hence v = ( = 2.04 m/s
Let h be the height by which the block rise. Applying law of conservation of energy
Potential energy of the combined bullet + block = Kinetic energy of the combination
(1/2)
h = /2g = 0.212 m
The heat produced = Initial kinetic energy of the bullet – final kinetic energy of the combination
= (1/2) - (1/2)
= (1/2
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