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Ray Optics and Optical Instruments

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3 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

In a compound microscope, the magnified virtual image is formed at a distance of $25 c m$ from the eye-piece. The focal length of its objective lens is $1 c m$ . If the magnification is 100 and the tube length of the microscope is $20 c m$ , then the focal length of the eyepiece lens (in $c m$ ) is

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alok kumar singh

Contributor-Level 10

$M = \frac{1}{f_{o}} [1 + \frac{D}{F e}]$

$\Rightarrow 100 = \frac{20}{1} [1 + \frac{25}{F e}]$

$\Rightarrow 1 + \frac{25}{F e} = 5$

$\Rightarrow F e = \frac{25}{4} = 6.25 c m$

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3 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a alight of wavelength 2440 $\overset{o}{A}$ is used to see the object will be

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Payal Gupta

Contributor-Level 10

Resolving power, = $\frac{d}{1.22 λ} = \frac{24.4 * 1 0^{- 2}}{1.22 * 2440 * 1 0^{- 10}}$

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3 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

The refracting angle of a prims is A and refractive index of the material of the prism is cot (A/2). Then the angle of minimum deviation will be

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Payal Gupta

Contributor-Level 10

At minimum deviation –

$δ = 2 i - A \Rightarrow i = \frac{δ + A}{2}, r = \frac{A}{2}$

Using snell's low : - $s i n i = μ = s i n r$

$\Rightarrow \frac{δ + A}{2} = \frac{π - A}{2} \Rightarrow δ = π - 2 A$

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3 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

A ball is thrown up vertically with a certain velocity so that, it reaches a maximum height h. Find the ratio of the times in which it is at height $\frac{h}{3}$ while going up and coming down respectively.

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Vishal Baghel

Contributor-Level 10

$h = \frac{u^{2}}{2 g} \Rightarrow u = \sqrt[]{2 g h}$

$\frac{h}{3} = \sqrt[]{2 g h} t - 5 t^{2}$

$5 t^{2} - \sqrt[]{20 h} t + \frac{h}{3} = 0$

$t = \frac{\sqrt[]{20 h} \pm \sqrt[]{20 h - 4 * 5 * \frac{h}{3}}}{10}$

$∴ \frac{t_{1}}{t_{2}} = \frac{\sqrt[]{20 h} - \sqrt[]{\frac{40}{3} h}}{\sqrt[]{20 h} + \sqrt[]{\frac{40}{3} h}} = \frac{1 - \sqrt[]{\frac{2}{3}}}{1 + \sqrt[]{\frac{2}{3}}} = \frac{\sqrt[]{3} - \sqrt[]{2}}{\sqrt[]{3} + \sqrt[]{2}}$

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3 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

A convex lens has power P. It is cut into two halves along its principal axis. Further one piece (out of the two halves) is cut into two halves perpendicular to the principal axis (as shown in figures). Choose the incorrect option for the reported pieces.

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Payal Gupta

Contributor-Level 10

$R_{1} = R$

$R_{2} = - R$

$P = \frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

$P = \frac{1}{f} = (μ - 1) (\frac{1}{R} - (\frac{- 1}{R}))$

P = \frac{(μ - 1) 2}{R}

L₂

R₁ = R

$R_{2} = \infty$

$R_{1} = \infty$

R₂ = -R

Power of $L_{1} = \frac{1}{f''} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

Power of $L_{1} = \frac{(μ - 1) * 2}{R} = P$

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3 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

The distance of the Sun from earth is 1.5 * 10¹¹ m and its angular diameter is (2000) s when observed from the earth. The diameter of the Sun will be

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Payal Gupta

Contributor-Level 10

1° → 60'

⇒ 60' → 10°

$60' \to {\frac{π}{180}}^{C}$

$θ = \frac{π * 2 * 1 0^{3}}{180 * 3600}$

L = 1.5 * 10¹¹ m

$D = L θ = 1.5 * 1 0^{11} * \frac{π}{180 * 3600} * 2 * 1 0^{3} = 1.45 * 1 0^{9} m$

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3 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

The distance of the Sun from earth is 1.5 × 10¹¹ m and its angular diameter is (2000) s when observed from the earth. The diameter of the Sun will be

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New question posted

3 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

The distance of the Sun from earth is 1.5 × 10¹¹ m and its angular diameter is (2000) s when observed from the earth. The diameter of the Sun will be:

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New answer posted

4 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 11th Chapter Six

Calculate the power of a crane in watts, which lifts a mass of 100 kg to a height of 10 m in 20s.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

m =100kg

Height h= 10m

Power= rate of work done =change of energy /time= mgh/t

= $\frac{100 * 9.8 * 10}{20} = 5 * 98 = 490 W$

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4 months ago

Ray Optics and Optical Instruments Physics NCERT Exemplar Solutions Class 12th Chapter Nine

An astronomical refractive telescope has an objective of focal length 20 m and an eyepiece of focal length 2 cm.

(a) The length of the telescope tube is 20.02 m

(b) The magnification is 1000

(c) The image formed is inverted

(d) An objective of a larger aperture will increase the brightness and reduce chromatic aberration of the

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(a, b, c) The length of the telescope tube L= f₀+f_e= 20+0.02= 20.02m

Also magnification is = 20/0.02= 1000

And image formed is inverted

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