Ray Optics and Optical Instruments

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New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

Maximum Distance = 3 (x + x) = 6x = 3 * 2x = 3 * 50 = 150 cm

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

VC=2GMR

Using conservation of Mechanical Energy

⇒−GMmR+12*m (Ve29)=−GMm (R+h)

⇒1R+h=89R⇒h=R8=64008=800  km

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

sin  iC=μrarerμdener=velocity  of  rorervelocity  of  denser

⇒sin  ic=1.5*1082*108=34

⇒tan  ic=37

⇒ic=tan−1 (37)

New answer posted

a year ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

Consider the following image dddddddddddddddddddddddddddddddddddddd

New question posted

a year ago

0 Follower 3 Views

New answer posted

a year ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

r^−i^=2cosθn^...... (1)

i^.n^=−cosθ...... (2)

⇒r^=i^−2 (i^.n^)n^

⇒b→=a→−2 (a→.c→)c→

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

T = 0.5 sec

No. of oscillation = 100

Resolution = 1 sec

l = 1 0 c m ± . 1 c m

               

New answer posted

a year ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

As,  1v−1u=1f⇒1v'+f−1μ'−f=1f

Also,  μ'v'=225

Using Newton's formula - μ'v'=f2

So, f2 = 225

f = 15 cm

 

New answer posted

a year ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

u = 100 cm

f=R2=−100cm

after 10 sec i=66=1A

u = 80 m

1v=1f−1u=1−100−1−80=180−1100=5−4400=1400

∴v=400cm

New answer posted

a year ago

0 Follower 30 Views

V
Vishal Baghel

Contributor-Level 10

Power of a lens, P = 1.25 m-1

μlens=1.5, r1=20cm, r2=40cm

As, P = 1f=1.25

⇒1.5μ1=16+1=76⇒μ1=67*1.5=97

 

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