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New answer posted
9 years agoContributor-Level 6
B.Sc biology degree serves as a basis for further higher studies in this field such as M.Sc, Ph.D and M.Phil degree in botany as well as in zoology, bio-chemistry, bio-technology, food science, biomedical sciences, genetics, molecular biology, microbiology, environmental sciences, virology, toxicology, etc. The successful completion of which makes one eligible for the post of a lecturer in any university/college.
B.Sc biology degree holders have plenty of opportunities in the field of research and development, pharmaceuticals and chemical industries, public health and environmental protection sector
New answer posted
9 years ago
Guide-Level 11
While a Bachelor's degree in general computer science will suffice, many schools offer 4-year degree programs specifically in network or computer engineering. These programs provide an overview of standard industry networking tools and procedures for resolving problems within computer networks. Classes cover topics like operating systems, programming essentials, network administration, and information security. Students may also gain instruction in specific networking systems, like Cisco.
Success tip:
To get the most out of your degree, complete an internship. Experience is essential to entering this career, and
New answer posted
9 years ago
Guide-Level 11
log a = kb-kc . (1)
log b = kc-ka . (2)
log c = ka-kb . (3)
Adding (1), (2) and (3), we get
log a + log b + log c = 0
log abc = 0
abc = 1
Solution 2:
Let (log a)/(b-c) = (log b)/(c-a) = (log c)/(a-b) = k, where k is a constant, then
log a = kb-kc . (1)
log b = kc-ka . (2)
log c = ka-kb . (3)
Multiply (1), (2) and (3) by a, b and c respectively:
alog a = kab-kac . (4)
blog b = kbc-kab . (5)
clog c = kac-kbc . (6)
Adding (4), (5) and (6), we get
alog a + blog b + clog c = 0
log a^a + log b^b + log c^c = 0
log (a^a)(b^b)(c^c) = 0
(a^a)(b^b)(c^c) = 1
New answer posted
9 years ago
Guide-Level 11
New answer posted
9 years ago
Guide-Level 11
New answer posted
9 years ago
Contributor-Level 9
New answer posted
9 years ago
Contributor-Level 9
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