States of Matter

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New answer posted

2 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

U n i t o f a n 2 V 2 = a t m

U n i t o f a = a t m * u n i t o f V 2 u n i t o f n 2

= a t m * ( d m 3 ) 2 m o l 2

= atm dm6 mol-2

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

T 1 = 2 7 ° C = 3 0 0 K T2 = 45° C = 45 + 273 = 318 K

P1 = 30 atmP2 =?

V is constant due to rigid tank\

P 1 T 1 = P 2 T 2

3 0 3 0 0 = P 2 3 1 8 P 2 = 1 1 0 * 3 1 8 = 3 1 . 8 a t m 3 2 a t m

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

T 1 = 2 7 ° C = 3 0 0 K  T2 = 45° C = 45 + 273 = 318 K

P1 = 30 atm        P2 =?

V is constant due to rigid tank

P 1 T 1 = P 2 T 2

3 0 3 0 0 = P 2 3 1 8 P 2 = 1 1 0 * 3 1 8 = 3 1 . 8 a t m 3 2 a t m    

New answer posted

3 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

V r m s > V a v > V m p

New answer posted

3 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Po2 = PTotal -   P N 2 5 = ( x / 3 2 x / 3 2 + 2 0 0 2 0 ) * 2 5 x = 8 0 g m

= 25 – 20 = 5bar

Po2 =   n O 2 n O 2 + n N e * P T o t a l

5 = ( x / 3 2 x / 3 2 + 2 0 0 2 0 ) * 2 5 x = 8 0 g m
 

New answer posted

3 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

For real gas under high pressure,

Z = 1 + P b R T b = R T P = 0 . 0 8 3 * 2 9 8 9 9        

= 0.25 * 10-2 L mol-1

New answer posted

3 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

V = 2 l , n = 0.25 Moles, P = 2 * 106 Pa, R = 8.314 J/mol.k

PV = nRT

2*106*2*103=0.25*8.314*T

T = 1654.7  1655 K

New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Pressure of gas = pressure of moist gas – Vapour pressure of water

= 4 atm – 0.4 atm

= 3.6 atm

On doubling the volume, pressure of gas is halved :

Total pressure =  ( 3 . 6 2 + 0 . 4 ) = 2 . 2 a t m

New answer posted

3 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

Po2 = PTotalPN2

= 25 – 20 = 5bar

Po2nO2nO2+nNe*PTotal

5= (x/32x/32+20020)*25x=80gm

New answer posted

3 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

PV)H2= (PV)Gas

(nRT)H2= (nRT)Gas

nH2*TH2=nGas*TGas

0.22*200=3 (MM)Gas*300 (MM)Gas=45gm/mole

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