States of Matter

Get insights from 92 questions on States of Matter, answered by students, alumni, and experts. You may also ask and answer any question you like about States of Matter

Follow Ask Question
92

Questions

0

Discussions

4

Active Users

0

Followers

New answer posted

4 weeks ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Correct order of van there Waals constant b for gases is CO2 > N2 > O2 > H2 > He

New answer posted

4 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

(A) Fluorspar                     –    CaF2

(B) Cryolite                 –    Na3 [AlF6]

(C) Bauxite                 –    Al2O3.2H2O

(D) Dolomite              –    MgCO3.CaCO3

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Since VReal > Videal

So, Z = VReal > 1. Videal

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

The Answer is Maxwell? Boltzmann distribution

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

NH3 can be liquefied most easily due to presence of strong intermolecular H-bonding among NH3 molecules.

New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Since VReal > Videal

So, Z = Real ideal V

New answer posted

a month ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

NH3 can be liquefied most easily due to presence of strong intermolecular H-bonding among NH3 molecules.

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

P 1 T 1 = P 2 T 2 3 5 3 0 0 = 4 0 T 2

T 2 = 4 0 * 3 0 0 3 5 = 3 4 2 . 8 5 K

T 2 ( ° C ) = 6 9 . 7 0 7 7 0 ° C

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

n R T P = 0 . 9 0 * 0 . 0 8 2 1 * 3 0 0 1 8 * 3 2 * 7 6 0 = 2 9 . 2 1 2 9

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Wt of liquid = 135 – 40 = 95 gm

Volume of liquid =  w t . d e n s i t y = 9 5 0 . 9 5 = 1 0 0 m l  

Hence volume of vessel = 100 ml = 0.1 lit from ideal gas equation,

M = d R T P = 0 . 5 0 . 1 * 0 . 0 8 2 1 * 2 5 0 0 . 8 2  

M = 1 2 5 g / m o l  

 

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 682k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.