Straight Lines
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Let two points be and . If a point be such that the area of sq. units and it lies on the line, , then a value of is:
Let two points be and . If a point be such that the area of sq. units and it lies on the line, , then a value of is:
Let the equation of the pair of lines, y = px and y = qx, can be written as (y - px)(y - qx) = 0. Then the equation of the pair of the angle bisectors of the lines x² - 4xy – 5y² = 0 is:
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Let the equation of the pair of lines, y = px and y = qx, can be written as (y - px)(y - qx) = 0. Then the equation of the pair of the angle bisectors of the lines x² - 4xy – 5y² = 0 is:
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x² - 4xy – 5y² = 0
Equation of pair of straight line bisectors is (x²-y²)/ (a-b) = xy/h
(x²-y²)/ (1- (-5) = xy/ (-2)
(x²-y²)/6 = xy/ (-2)
x²-y² = -3xy
x² + 3xy - y² = 0
If the locus of the mid-point of the line segment from the point (3, 2) to a point on the circle, x2 + y2 = 1 is a circle of radius r, then r is equal to:
If the locus of the mid-point of the line segment from the point (3, 2) to a point on the circle, x2 + y2 = 1 is a circle of radius r, then r is equal to:
=>
=>
circle of radius r =
A man is walking on a straight line. The arithmetic mean of the reciprocals of the intercepts of the line on the coordinate axes is <!-- [if gte mso 9]><xml>
</xml><![endif]--> Three stones A, B and C are placed at the point (1, 1), (2, 2) and (4, 4) respectively. Then which of these stones is / are on the path of the man?
A man is walking on a straight line. The arithmetic mean of the reciprocals of the intercepts of the line on the coordinate axes is <!-- [if gte mso 9]><xml>
According to question,
Equation of required line is
Obviously B (2, 2) satisfying condition (i)
If the area of the triangle formed by the positive x-axis, the normal and the tangent to the circle (x - 2)2 + (y – 3)2 = 25 at the point (5, 7) is A, then 24A is equal to………………
If the area of the triangle formed by the positive x-axis, the normal and the tangent to the circle (x - 2)2 + (y – 3)2 = 25 at the point (5, 7) is A, then 24A is equal to………………
Equation of normal is 4x – 3y + 1 = 0
Equation of tangent is 3x + 4y – 43 = 0
Area of triangle =

If the curve y = ax2 + bx + c, <!-- [if gte mso 9]><xml>
</xml><![endif]--> passes through the point (1, 2) and the tangent line to this curve at origin is y = x, then the possible values of a, b, c are:
If the curve y = ax2 + bx + c, <!-- [if gte mso 9]><xml>
y = ax2 + bx + c
a + b + c = 2
It passes through (0, 0)
0 = 0 + 0 + c -> c = 0
a = 1
If the curves x = y4 and xy = k cut at right angles, then (4k)6 equal to………….
If the curves x = y4 and xy = k cut at right angles, then (4k)6 equal to………….
Let a, b, c be in arithmetic progression. Let the centroid of the triangle with vertices (a, c), (2, b) and (a, b) be <!-- [if gte mso 9]><xml>
</xml><![endif]-->. If a, b are the roots of the equation <!-- [if gte mso 9]><xml>
</xml><![endif]--> then the value of <!-- [if gte mso 9]><xml>
</xml><![endif]--> is:
Let a, b, c be in arithmetic progression. Let the centroid of the triangle with vertices (a, c), (2, b) and (a, b) be <!-- [if gte mso 9]><xml>
2a + 2 = 0
2a = 8 -> a = 4 .(i)
and
2b + c = 7 .(ii)
Since a, b, c are in A.P.
2b = a + c
From (i) 2b = 4 + c .(iii)
Solving (ii) and (iii)
4 + c + c = 7
2
The locus of the point of intersection of the lines <!-- [if gte mso 9]><xml>
</xml><![endif]-->= 0 is a conic, whose eccentricity is…………………
The locus of the point of intersection of the lines <!-- [if gte mso 9]><xml>
K
K =
48 = 16 (e2 – 1)