Straight Lines

Get insights from 177 questions on Straight Lines, answered by students, alumni, and experts. You may also ask and answer any question you like about Straight Lines

  • 177

    Questions

  • 0

    Discussions

  • 0

    Active Users

  • 0

    Followers

Have a question about Straight Lines? Ask our experts

Ask Your Question

Keep it short & simple. Type complete word. Avoid abusive language.

New answer posted•a year ago
S
a year ago

Line BM : 2x + y = 3 Þ M (0, 3)

Line CD : 7x – 4y = 1 Þ C (3, 5)

Mirror image of A (-3, 1) in the line CD is ( 1 3 5 , − 1 1 5 )  and it will lie on BC.

Slope of AC is 2/3

Slope of BC is 18.

t a n θ = 1 8 − 2 3 1 + 1 8 ( 2 3 ) = 4 3   

 where θ = ∠ A C B  

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Circumcentre (D) ≡ (5, α4)

(5−α)2+ (α4+2)2= (5−α)2+ (α4−6)2............... (i)

(5−α4)2+ (α4+2)2.................... (ii)

(i) α4+2=± (α4−6)

(ii) 9 + 16 = 9 + 16

⊕→x

(−)→α2=4⇒α=8

ar  (ABC)=24

2S = 24

R = 5, r = Δs=2412=2

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

m1m2=−1, for square a,b,c,d let

A(10(cosα−sinα),10(sinα+cosα))

Diagonal : (cosα - sinα)x + (sinα + cosα)y = 10

BD (diagonal)

Dist. Of BD from A is

|10(cosα−sinα)2+10(sinα+cosα)2−10|2=a2

102=a2⇒a=10

Also, a2 + 11a + 3 (m12+m22)=220

210 + 3 (cm12+m22)=220

m12+m22=103

Also, m1 m2 = -1

m2 + 1m2=103

or −3,13

m = 3,−13

m4−103m2+1=0⇒m2=103±1009−42−103±832=3,13

m = ±3,±13

Diagonal AC:

(sinα+cosα)x−(cosα−sinα)y

=10 cos2α - 10cos2α = 0

Slope of AC = sinα+cosαcosα−sinα=tanα+11−tanα=tan(α+π4)α=30°

FIGURE

? = 72(116+916)+100−30+13=72016+83=128

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

| h | = r     a n d     | h | + k 1 2 = r

( h + k ) 2 2 = h 2 ⇒ h 2 = k 2 + 2 h k
x 2 − y 2 = 2 x y

 

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

Δ 1 Δ 2 = | 1 1 1 x − 4 x − x 1 − 4 3 1 | | 1 1 1 − 4 3 1 − 2 − 5 1 | = 4 7

->14 x – 35 y = -95        …. (ii)

Solve (i) & (ii), x =    − 2 0 7 , y = − 1 1 7

a r Δ A Q R

= 1 2 × 1 × 1 = 1 2                

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

Required area (above x-axis)

A 1 = 2 ∫ 0 4 ( 8 − x 2 − x ) d x            

= 2 ( 1 6 − 1 6 4 − 8 3 / 2 ) = 4 0 3                

and A 2 = 4 ( 1 2 . k 2 ) = 2 k 2  

∴ 2 7 . 4 0 3 = 5 . ( 2 k 2 )

-> k = 6

for above x-axis.

 

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

  d y d x = a x − b y + a b x + c y + a

= b x d y + c y     d y + a d y = a x   d x − b y   d x + a d x                

= c y 2 2 + a y − a x 2 2 − a x + b x y = k              

a x 2 + a y 2 + 2 a x − 2 a y = k            

⇒ x 2 + y 2 + 2 x − 2 y = λ              

Short distance of (11,6)

= 1 2 2 + 5 2 − 5

= 13 – 5

= 8

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

Circumcentre (D) ≡ ( 5 , α 4 )  

( 5 − α ) 2 + ( α 4 + 2 ) 2 = ( 5 − α ) 2 + ( α 4 − 6 ) 2 . . . . . . . . . . . . . . . ( i )

( 5 − α 4 ) 2 + ( α 4 + 2 ) 2 . . . . . . . . . . . . . . . . . . . . ( i i )

 (i) -> α4+2=±(α4−6)  

(ii) -> 9 + 16 = 9 + 16

⊕ → x

( − ) → α 2 = 4 ⇒ α = 8

ar   ( A B C ) = 2 4

2S = 24

R = 5, r =   Δ s = 2 4 1 2 = 2

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

m 1 m 2 = − 1 , for square a,b,c,d let

A ( 1 0 ( c o s α − s i n α ) , 1 0 ( s i n α + c o s α ) )           

Diagonal : (cos a - sina)x + (sina + cosa)y = 10

BD (diagonal)

Dist. Of BD from A is

| 1 0 ( c o s α − s i n α ) 2 + 1 0 ( s i n α + c o s α ) 2 − 1 0 | 2 = a 2               

  1 0 2 = a 2 ⇒ a = 1 0             

Also, a2 + 11a + 3  

...Read more

Thumbs Up IconUpvote Thumbs Down Icon