The S-block Elements
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4 months agoContributor-Level 10
(d) BaCO3
Thermal stability is directly proportional to the size of the cation i.e., larger the size of the atom, greater is its thermal stability. Ba being the biggest cation among the given compounds, has a greater thermal stability.
New answer posted
4 months agoContributor-Level 10
(a) Li
Li+ is the smallest in size and thus, has the highest charge density and hence attracts the water molecules more strongly to form hydrated salts.
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4 months agoContributor-Level 10
(d) Cs
Size of Cs is the biggest thus, its melting point is the lowest, (d) is correct
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4 months agoContributor-Level 10
(i) Lattice energy of BeO is comparatively higher than the hydration energy. Therefore, it is almost insoluble in water. Whereas, BeSO4 is ionic in nature and its hydration energy dominates the lattice energy.
(ii) Both BaO and BaSO4 are ionic compounds but the hydration energy of BaO is higher than the lattice energy therefore it is soluble in water.
(iii) Since the size of Li+ ion is very small in comparison to K+ ion, it polarises the electron cloud of I– ion to a great extent. Thus, Lil dissolves in ethanol more easily than the KI.
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4 months agoContributor-Level 10
(a) Na2O2 + 2H2O → 2NaOH + H2O2
(b) 2KO2 + 2H2O → 2KOH + O2+ H2O2
(c) Na2O+ CO2 → Na2CO3
New answer posted
4 months agoContributor-Level 10
(a) Na2CO3 is a salt of a weak acid, carbonic acid (H2CO3) and a strong base NaOH. Thus, it undergoes hydrolysis to produce strong base NaOH and its aqueous solution isalkaline in nature.
Na2CO3 (s) + H2O (l) → 2NaOH
(b) Because the discharge potential of alkali metals is much higher than that of hydrogen, therefore when the aqueous solution of any alkali metal chloride is subjected to electrolysis, H2, instead of the alkali metal, is produced at the cathode. Therefore, alkali metals are prepared by electrolysis of their fused chlorides.
(c) Since potassium is move reactive than sodium and it is found in nature to a less extent
New answer posted
4 months agoContributor-Level 10
(a) Smaller the size of the ion, more highly it is hydrated and hence greater is the mass of the hydrated ion and thus the ionic mobility become lesser. The extent of hydration decreases in the order.
Li+ < Na+
Thus the mobility of Cs+ will be the highest
(b) Due to its smaller size lithium can form nitride directly as an exceptional behaviour unlike other alkali metals.
(c) It is because reduction potential depends upon sublimation energy, ionisation energy and hydration energy. Their resultant is almost constant for these ions.
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4 months agoContributor-Level 10
(i) 2Na + 2H2O → 2NaOH + H2
(ii) 2Na + O2 → Na2O2
(iii) Na2O2 + 2H20 → 2NaOH + H2O2
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