Thermodynamics
Get insights from 324 questions on Thermodynamics, answered by students, alumni, and experts. You may also ask and answer any question you like about Thermodynamics
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(a), (b), (d) When the rod is hammered the external work is done on the rod which increases its temperature.
Heat is transferred to the gas in the small container by big reservoir at temperature T2
As the weight is added to the cylinder arrangement in the form of external pressure so it cannot reversed.
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(b) Let us assume that T1, T2T3
According to questions there is no loss of heat in the surroundings
Heat lost by M3 = heat gained by M1+ heat gained by M2
M3s (T3-T)= M1s (T-T1)+M2s (T-T2)
T [M1+M2+M3]= M3T3+M1T1+M2T2
T =
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(a) Container A is isothermal and container B is adiabatic

For isothermal process P1V1=P2V2
Po (2Vo)= P2 (Vo)
P2= 2Po
for adiabatic process
P1V1y= P2V2y
Po (2Vo)y=P2 (Vo)y
P2= ( )yPo= 2yPo
Hence ratio of final pressure =
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(b) Work done ABCD = area of rectangle ABCDA
= AB = (3Vo-Vo) (2po-po)
= 2V0 Po= 2poVo
And work done by the gas =- 2poVo
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(c) As we know PV =constant
Hence we can say that gas is going through an isothermal process.
Clearly from the graph that between process 1 and 2 temperature is constant and the gas expands and pressure decreases. So density of 2 is less than 1 so option ii
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(a) Amount of sweat evaporated /minute =
=
New answer posted
4 months agoContributor-Level 10
This is a multiple choice answer as classified in NCERT Exemplar
(c) For the curve 1 volume is constant so it is isochoric process. But in curve 2 and 3 curve 2 is steeper so 2 is adiabatic and 3 is isothermal.
New answer posted
4 months agoContributor-Level 10

process 1 isochoric and process 2 is isothermal .
Since, work done = area under P-V curve . here area under the pV curve 1 is more . so work done is more when the gas expands in isochoric process.
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Coefficient of
T1= 27+273=300K
Coefficient of performance
1500-5T2=T2
6T2=1500
T2= 250K
T2= 250-273=-23oC
New answer posted
4 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
Temperature of the source is 270C
T1= 27+273= 300K
T2= -3+273= 270K
Efficiency of heat engine = 1-T2/T1= 1-270/300=1/10
Efficiency of refrigerator is 50% of a perfect engine
= 0.5 = 1/20
Coefficient of performance of the refrigerator
=
Q2= =19W
= 19 1KW=19KW= 19kJ/s
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers