Thermodynamics
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New answer posted
6 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
Molar enthalpy change for graphite (ΔH)
= enthalpy change for 1 g x molar mass of C = -20.7*12 = -2.48 x 102 kJ mol-1
Since the sign of ΔH = -ve, it is an exothermic reaction.
New answer posted
6 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
Given that, Cv = heat capacity at constant volume,
Cp = heat capacity at constant pressure
Difference between Cp and Cv is equal to gas constant (R).
.'. Cp – Cv = nR (where, n = no. of moles)
= 10 x 8.314 = 83.14J
New answer posted
6 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
For water, molar heat capacity = 18 x Specific heat or Cp = 18 x c
But, specific heat,
C = 4.18 J g-1 K-1 Heat capacity,
Cp = 18 x 4.18 JK-1 = 75.24 JK-1
New question posted
6 months agoNew answer posted
6 months agoContributor-Level 10
36. Graphite has greater entropy since it is loosely packed. At absolute zero the entropy of a substance is zero.
New answer posted
6 months agoContributor-Level 10
This is a Short Answer Type Questions as classified in NCERT Exemplar
During free expansion, external pressure is zero, so Work done, w = -pextΔV
= -0(5 – 1) = 0
Since the gas is expanding isothermally, therefore, q = 0
ΔU = q + w =0+0=0
New question posted
6 months agoNew answer posted
6 months agoContributor-Level 10
34. For diatomic molecules e.g. H2, O2, Cl2 etc. both energies are equal.
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