Alternating Current

7.3 Inductance of the Inductor, L = 44 mH = 44 $*{10}^{-3}$ H

Supply voltage, V = 220 V

Supply frequency,  $\nu$ = 50 Hz

Angular frequency,  $\omega$ = 2 $\pi \nu$

Inductive reactance,  $X_L$ = $\omega L$ = 2 $\pi \nu L$

rms value of current is given as

I = $\frac{V}{X_L}$ = $\frac{220}{2\pi *50*44\mathrm{}*{10}^{-3}}$ = 15.92 A

Hence, the rms value of the current in the circuit is 15.92 A.

7.2 Peak voltage of the AC supply,  $V_o$ = 300 V

RMS voltage is given by $V_{rms}$ = $\frac{\mathrm{}{V}_o}{\surd 2}$ = $\frac{\mathrm{}300}{\surd 2}$ = 212.13 V

The rms value of current, I = 10 A

Peak current $I_o$ = $\sqrt[]{2}I$ = $\sqrt[]{2}*10=14.1A$

7.1 Resistance of the resistor, R = 100 Ω

Supply voltage, V = 220 V

Supply frequency,  $\nu$ = 50 Hz

The rms value of current is given as, I = $\frac{V}{R}$ = $\frac{220}{100}$ = 2.2 A

The net power consumed over a full cycle is given as P = VI = 220 $*2.2$ = 484 W