B.E.
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New answer posted
a year agoContributor-Level 9
If the preceding three years are to be considered, the DY Patil Akurdi cutoff trend for BE Computer Engineering has been falling. The DY Patil Akurdi cutoff for the B.E. in computer engineering in 2023 was 35755, which is less than the 2022 cutoff of 40075, which was also less than the 2021 cutoff of 82260.
New answer posted
a year agoContributor-Level 9
Applicants must have passed their 10+2 (or equivalent) exam with math, chemistry, and physics as required courses. A minimum cumulative score of 50% in mathematics, chemistry, and physics was required of candidates. The TNEA counselling process, which considers your 12th standard marks, is the main factor determining admission. TNEA admission examinations are not distinct exams. Applicants with valid scores on admission exams such as JEE Main may also be taken into consideration on occasion.
New answer posted
a year agoContributor-Level 10
Sri Krishna College of Technology has an intake of 1,200 seats for its BE/BTech programme. These seats have been distributed among various specialisations including Civil Engineering, Mechanical Engineering, Electronics and Communication Engineering, Computer Science and Engineering, and more. Allocation of these seats is facilitated throughout TNEA counselling. Moreover, BE seat allocation is subject to applicants' rank based on TNEA exam scores and institute's intake.
New answer posted
a year agoContributor-Level 10
SKCT Coimbatore admits students to its various BE/BTech courses via TNEA Cousnelling. Thus, TNEA counselling process becomes a key event for the SKCT admission process. As per official sources, the counselling process is expected to start in the month of July. Students are advised to keep visiting the official website of TNEA to stay updated.
New answer posted
a year agoContributor-Level 10
Sri Krishna College of Technology BE/BTech eligibility criteria is common for all specializations. Students can refer to the below table to know the eligibility criteria:
Course | Eligibility criteria |
|---|---|
BE/BTech at SKCT | - General category candidates: A candidate with a minimum of 45% in Maths, Physics, and Chemistry in Class 12 examinations is eligible to apply - SC/ST/SCA candidates: For students from other categories, the eligibility requirement is a minimum of 45% marks in Maths, Physics, and Chemistry in Class 12 examinations. |
New answer posted
a year ago
Contributor-Level 10
There is no age limit to appear for the IRMASAT selection process. However, candidates should hold a Bachelor's degree from a recognised board or institute. They must also have a valid score in CAT, XAT or CMAT to take part in the IRMASAT selection process and online personal interviews.
New answer posted
a year ago
Contributor-Level 10
The B.E. programme offered at the college has a fee range of INR 1.8 Lacs to 2 lakh. To be eligible for admission, it is mandatory to pay a certain amount of fee at the time of admission to grab the final seat. The aforementioned data has been collated from the official website.
New answer posted
a year agoBeginner-Level 4
To be precise, you can't get direct admission in RCET as college its own criteria which involves.
- Decent rank JEE or in state entrance exam.
- High school qualification with decent score.
And possibly some other requirements of college
New answer posted
a year agoContributor-Level 10
Sardar Vallabhbhai Patel Institute of Technology GUJCET Cutoff 2024 was released for Round 1. The Cutoff was released for different categories under the HS Quota. The Cutoff ranged between 7012 and 38600, for the General HS category candidates. The Cutoff for B.E. in Computer Engineering closed at 7012, for the General HS category candidates.
For the OBC HS category candidates, the Cutoff for BE in Computer Engineering closed at 13610. For the ST and the SC category candidates, the Cutoff for CE closed at 35905 and 19521, respectively.
For the PWD category candidates, the Cutoff closed at 4843 for BE in CE.
For the EWS c
New answer posted
a year agoContributor-Level 10
CHARUSAT GUJSAT Cutoff 2024 was released for Round 1. The Cutoff was released as Opening and Closing, for AI and HS category candidates. The most competitive course for the General HS category candidates was BTech in CSE, with the closing Cutoff of 1832.
For the OBC HS category candidates, the Cutoff closed at 3255, making it the most competitive course.
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