Chemistry Coordination Compounds

In H₂O (polar solvent) dibromophenol derivative and in CS₂ (non-polar solvent moneobromo phenol derivate is obtained.

3d => 4d => 5d CFSE increases for the same ligands.

${\mathrm{M}\mathrm{a}}_2{\mathrm{b}}_2{\mathrm{c}}_2=5$ Geometrical Isomers

M (AA)b2c2:3  $\mathrm{M}\left(\mathrm{A}\mathrm{A}\right){\mathrm{b}}_2{\mathrm{c}}_2:3$  Geometrical Isomers

In ${\left. [\mathrm{F}\mathrm{e}?{\left({\mathrm{H}}_2\mathrm{O}\right)}_5\left(\mathrm{N}\mathrm{O}\right)\right]}^{2+}$

${\mathrm{F}\mathrm{e}}^{+1}\left(3{\mathrm{d}}^7\right)$

In ${\left. [{\mathrm{C}\mathrm{r}}^{+3}(\mathrm{C}\mathrm{N}{)}_6\right]}^{3-}$

${\mathrm{C}\mathrm{r}}^{+3}\left(3{\mathrm{d}}^3\right)$

 0.2 mole gives $\to 0.4$ $$ mole of $$ $\mathrm{A}\mathrm{g}\mathrm{C}\mathrm{l}$ (moles of $\mathrm{A}\mathrm{g}\mathrm{C}\mathrm{l}=\frac{57.45}{143}=0.4$ $\frac{}{}$ )

1 mole complex gives $\to \frac{0.4}{0.2}=2$ $\frac{}{}$ moles $\mathrm{A}\mathrm{g}\mathrm{C}\mathrm{l}$ $$

The correct answer should be $2^{\text{nd}}$ ${}^{}$ option.

Factual
⇒ leaching methods is used for those metal in which metal is more soluble than impurities and these are Al, Au, Ag, low grade Cu

σ bonded organometallic compound ⇒ M – C
σ-bond
and in π – bonded organo metallic compound
M – C
π bond
In ferrocene, there is π-bond

(a)  [1rCl (CO) (PPh₃)₂] carbonylchloridobis (triphenylphosphine) iridium (I).

(b)  Coordination number of Ir is four. Ir is in (+1) oxidation state with 4d⁸ configuration. It is trans isomer, so its geometry should be square planar.

(c) All electrons are paired, hence diamagnetic

(d)  Can exhibit GI only.

${\Delta }_t=\frac{hc}{\lambda }=\frac{6.63*10^{-34}*3.08*10^8}{600*10^{-9}}$

$=\frac{6.63*3.08*10^{-17}}{600}$ J

$=765.765*10^{-21}J$

$?766*10^{-21}$ J

The given value of µ (spin only)
2.84 = √n (n + 2) BM, So, n = 2
Among the given configurations, d? system in strong field ligand will have 2-unpaired e? in t? g set of orbitals as shown below.