Chemistry Coordination Compounds

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New answer posted

3 weeks ago

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A
alok kumar singh

Contributor-Level 10

EAN = Atomic No. – Oxidation state + 2 * CN

= 26 – 2 + 2 * 6

= 36.

New answer posted

4 weeks ago

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A
alok kumar singh

Contributor-Level 10

 

 

Cis (optically active)                          Trans (optically inactive)

d & l form (2)                                                    (1)

So, total 3 isomerism.

New answer posted

4 weeks ago

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V
Vishal Baghel

Contributor-Level 10

CoCl3.NH3 + AgNO3 A g C l ( 2 m o l )  

[ C o ( N H 3 ) 5 C l ] C l 2 + A g N O 3 A g C l ( 2 m o l )  

x = 5

New answer posted

4 weeks ago

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A
alok kumar singh

Contributor-Level 10

For precipitation of two moles of AgCl

Two Cl- will produce as a free anion

CoCl3.4NH3 -> complex will [ C O ( N H 3 ) 4 C l 2 ]  Cl (will not give 2Cl-)

P t C l 4 . 2 H C l  complex will be H2 [PtCl6] will not any Cl-

N i C l 2 . 6 H 2 O [ N i ( H 2 O ) 6 ] C l 2  will produce two Cl- ion.

[ N i ( H 2 O ) 6 ] + + + 2 C l A g N O 3 2 A g C l ( s )  precipitate formation

N i 2 + [ A r ] 3 d 8 4 s 0  

 

New answer posted

4 weeks ago

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R
Raj Pandey

Contributor-Level 9

All metal carbonyls have synergic bonds

New answer posted

4 weeks ago

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A
alok kumar singh

Contributor-Level 10

CoCl3.NH3 + AgNO3 A g C l ( 2 m o l )

[ C o ( N H 3 ) 5 C l ] C l 2 + A g N O 3 A g C l ( 2 m o l )  

x = 5

New answer posted

4 weeks ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

M n 2 + t 2 g 1 1 1 e g 1 1

(Number of unpaired electron = 5)

μ S = 3 5 = 5 . 9 1 6

New answer posted

4 weeks ago

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R
Raj Pandey

Contributor-Level 9

[ N i ( C N ) 4 ] 2  

CN- is strong field ligand


N i 2 + = 4 s 0 3 d 8  

 Here; [ N i ( C N ) 4 ] 2 is square planar and diamagnetic.

[ N i ( C O ) 4 ]  

Ni = 4s23d8         Co is strong field ligand.

Here ;  [ N i ( C O ) 4 ]  is tetrahedral and diamagnetic

[ N i ( C N ) 4 ] 2  has 3d8 configuration while [ N i ( C O ) 4 ]  has 3d10 configuration.

New answer posted

4 weeks ago

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A
alok kumar singh

Contributor-Level 10

 

From the given structure of CuSO4 . 5H2O Cu (II) ion and oxygen bonds are present but ligands coordinating with Cu (II) ion are not O and S both.

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

[ C u ( e n ) 2 ( S C N ) 2 ]

More stable isomers = 3 (trans isomers)

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