Chemistry Coordination Compounds
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New answer posted
a month agoContributor-Level 10
BF? behaves as Lewis acid due to incomplete octet in valence shell of Boron. Hence it can accept a lone pair of electrons.
New answer posted
a month agoContributor-Level 10
More the number of strong field ligands in a complex greater the energy absorbed by a complex.
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a month agoContributor-Level 10
[Ag (H? O)? ]? [Ag (CN)? ]? is called diaquasilver (I)dicyanidoargentate (I).
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a month agoContributor-Level 9
The complex CoCl? ·4NH? is represented as [CoCl? (NH? )? ]Cl.
Here, 4 NH? are neutral monodentate ligands. So, 2 equivalents of ethylene diamine replace 4NH? since ethylene diamine is a didentate ligand.
New answer posted
a month agoContributor-Level 10
The energy is calculated using the formula Δ? = hc/λ. Plugging in the values for Planck's constant (h), the speed of light (c), and the given wavelength gives an energy of 3.99 * 10? ¹? J. The answer is requested as a single digit.
Answer: 4 (in units of 10? ¹? J)
New answer posted
a month agoContributor-Level 10
The magnetic moment of an ion is determined by its number of unpaired electrons (n). For the given lanthanide ions:
o Ce? has 0 unpaired electrons (4f? ).
o Eu³? has 6 unpaired electrons (4f? ).
o Gd³? has 7 unpaired electrons (4f? ).
Gd³? has the highest number of unpaired electrons and therefore the highest magnetic moment.
New answer posted
a month agoContributor-Level 9
CuSO? 5H? O is blue vitriol which is represented as [Cu (H? O)? ]. H? O.SO? Here, secondary valencies are 4 H? O and 1H? O molecule outside coordination sphere is involved in hydrogen bonding.
New answer posted
a month agoContributor-Level 10
1° amine: Forms a precipitate that is soluble in NaOH.
2° amine: Forms a precipitate that is insoluble in NaOH.
3° amine: No reaction.
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