Chemistry Coordination Compounds
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New answer posted
a month agoContributor-Level 10
Formation of passive layer of Fe? O? on the surface of Fe and NO? gas is evolved
[Co (NH? )? ]³? is diamagnetic (t? g? eg? ) and is inner orbital complex
New answer posted
a month agoContributor-Level 10
Stability constant are :
K1 = 104
K2 = 1.58 * 103
K3 = 5 * 102
K4 = 102
Overall stability constant K will be
K = K1 * K2 * K3 * K4
= 7.9 * 1011
Now, overall equilibrium constant for dissociation of [Cu (NH3)4]2+ is
= 1.26 * 10-12
So; x = 1 (Rounded off to the nearest integer)
New answer posted
a month agoContributor-Level 10
3 [Co (en)? Cl? ]Cl + 3AgNO? (excess) → 3AgCl↓ (ppt) + 3 [Co (en)? Cl? ] NO?
Secondary valency of complex = 6
New answer posted
a month agoContributor-Level 10
[Mn (CN)? ]³? → Mn³? i.e 3d? → t? g? , eg? (d²sp³), CN? is strong field ligand.
[Fe (CN)? ]³? → Fe³? i.e 3d? → t? g? , eg? (d²sp³), CN? is strong field ligand.
[Co (C? O? )? ]³? → Co³? i.e, 3d? → t? g? , eg? (d²sp³), C? O? ²? is strong field ligand.
[MnCl? ]? → Mn³? = 3d? → t? g²¹¹¹, eg¹¹? (4 unpaired e? ), Cl? is weak field ligand.
[FeF? ]³? → Fe³? = 3d? → t? g³¹¹, eg²¹¹ (5 unpaired e? ) F? is strong field ligand.
∴ S? and S? are true.
New answer posted
a month agoContributor-Level 10
One edge of an cube is common to four unit cells. Hence One edge centre OV contribute 1/4 to one unit cell.
New answer posted
a month agoContributor-Level 10
Homoleptic complexes have all ligands identical. Potassium trioxalatoaluminate (III) is K? [Al (C? O? )? ] which has only oxalate ion as ligand. All others have more than one type of ligands.
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