Chemistry NCERT Exemplar Solutions Class 11th Chapter One

Due to the larger acid dissociation constant (Ka) sulphuric acid acts as an acid and HNO₃ acts as a base.

$\left[C{l}^{-}\right]=10^{-1}M$

$\left[Cr{O_4}^{--}\right]=10^{-3}M$

for AgCl ppt¹, ${\left[A{g}^{+}\right]}_{req}=\frac{1.7*10^{-10}}{10^{-1}}M$  

For Ag₂CrO₄ppt², ${\left[A{g}^{+}\right]}_{req}=\sqrt[]{\frac{1.9*10^{-12}}{10^{-3}}}M$

${\left[A{g}^{+}\right]}_{req}=4.3*10^{-5}M$

Being lower concentration of [Ag⁺] in case of AgCl, it will precipitate first.

Kindly consider the following figure

Regarding industrial consumption of H₂ manufacturing of NH₃ is the largest applications.

Due to the absence of acidic hydrogen in But – 2-yne, metallic sodium does not react with this.

In metamers, distribution of alkyl groups are changed with respect to polyvalent functional groups.

ln $Cul,C{u}^{+}has3d^{10}4s^0,\left[n=0and\mu =0BM\right]$

ln   $\left[Cu{\left(N{H}_3\right)}_4\right]C{l}_2,C{u}^{++}has3d^{9}4s^0\left[n=1and\mu =1.73BM\right]$

$ln{O}_2^{-}\&{O_2}^{+}$ only one electron is unpaired in anti bonding MO,

Hence [n = 1 and $\mu$ = 1.73 BM]