Chemistry NCERT Exemplar Solutions Class 11th Chapter Seven
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4 months agoContributor-Level 10
This is a Matching Type Questions as classified in NCERT Exemplar
Ans: (i) → (b); (ii) → (e); (iii) → (c); (iv) → (d)
New answer posted
4 months agoContributor-Level 10
This is a Matching Type Questions as classified in NCERT Exemplar
Ans: (i) → (d); (ii) → (a); (iii) → (b).
New answer posted
4 months agoContributor-Level 10
This is a Matching Type Questions as classified in NCERT Exemplar
Ans: (i) → (d); (ii) → (c); (iii) → (b)
New answer posted
4 months agoContributor-Level 10
This is a Matching Type Questions as classified in NCERT Exemplar
Ans: (i) → (b); (ii) → (d); (iii) → (c); (iv) → (a).
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: options (i) and (iv)
Ice and water are in equilibrium only at particular temperature and pressure. For any pure substance at atmospheric pressure, the temperature at which the solid and liquid phases are at equilibrium is called the normal melting point or normal freezing point of the substance. For example, it is 4°C in case of water. The system here is in dynamic equilibrium.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans:, option (i), (iii) and (iv)
As, K increases with increase in temperature. K increases, it shows that the reaction must be endothermic. No. of molecules increases thus, there is increase in entropy.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: option (iv)
Since in all the given reaction, the volume is to be kept constant and an inert gas argon is added which will do not take part in reaction. So, the equilibrium will remain unaffected in all the given cases.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: option (i)
If the equation is multiplied by 2, the equilibrium constant for the new equation is the square of K it means we must do the square of 5 that is 25. Then and on reversing the reaction the value of the equilibrium constant is inversed means the value of K comes out to be 1/25= 0.04.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: option (ii)
Greater the boiling point, lower will be the vapour pressure.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option(i)
The given reaction is :-
N2 (g) + 3H2 (g) ?2NH3 (g)
A/C to vart Hoff's eqn,
=
K is dependent on temperature. As temperature remains constant at equilibrium, so K will remain constant in the given conditions.
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